小编pip*_*lam的帖子

在主题中，我想将日期作为参数传递。我有这个依赖：

<dependency>
            <groupId>com.fasterxml.jackson.datatype</groupId>
            <artifactId>jackson-datatype-jsr310</artifactId>
        </dependency>

我的URL样子：

http://localhost:8080/userProducts/2?date=2019-3-29

我的控制器类看起来像：

package trainingapp.userproduct;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.format.annotation.DateTimeFormat;
import org.springframework.web.bind.annotation.*;
import trainingapp.calculations.NutrientsCalculationFacade;
import trainingapp.historysystemofmeals.HistorySystemService;

import java.time.LocalDate;
import java.time.LocalDateTime;
import java.util.List;

@RestController
public class UserProductController {

    private final NutrientsCalculationFacade userProductCalculationFacade;
    private final UserProductFindOperationService userProductFindOperationService;
    private final HistorySystemService historySystemService;

    @Autowired
    public UserProductController(NutrientsCalculationFacade userProductCalculationFacade, UserProductFindOperationService userProductFindOperationService, HistorySystemService historySystemService) {
        this.userProductCalculationFacade = userProductCalculationFacade;
        this.userProductFindOperationService = userProductFindOperationService;
        this.historySystemService = historySystemService;
    }

    //yyyy-MM-dd
    @GetMapping("/userProducts/{userID}")
    public String getAllEatenSummedNutrientsByGivenIDInParticularDay(@PathVariable int userID,
                                                                     @RequestParam("date")
                                                                     @DateTimeFormat(iso = DateTimeFormat.ISO.DATE) LocalDate date) {
        return historySystemService.getAllEatenSummedNutrientsByGivenIDInParticularDay(userID, …

嘿，我遇到了与这里相同的问题：JSON Java 8 LocalDateTime format in Spring Boot我尝试了那里的解决方案，但它不起作用。有人可以告诉我我做错了什么吗？

我添加了

spring.jackson.serialization.write-dates-as-timestamps=false\n

到 application.property\n我的模型类如下所示：

package bookrental.model.book;\n\nimport bookrental.model.account.User;\nimport com.fasterxml.jackson.annotation.JsonFormat;\nimport com.fasterxml.jackson.databind.annotation.JsonDeserialize;\nimport com.fasterxml.jackson.databind.annotation.JsonSerialize;\nimport com.fasterxml.jackson.databind.util.ISO8601DateFormat;\nimport com.fasterxml.jackson.datatype.jsr310.deser.LocalDateTimeDeserializer;\nimport com.fasterxml.jackson.datatype.jsr310.ser.LocalDateTimeSerializer;\nimport lombok.*;\n\nimport javax.persistence.*;\nimport java.time.LocalDateTime;\nimport java.util.Date;\n\n@Entity\n@Getter\n@Setter\n@EqualsAndHashCode\n@AllArgsConstructor\n@NoArgsConstructor\npublic class BookRentals {\n\n    @Id\n    @GeneratedValue(strategy = GenerationType.AUTO)\n    private int id;\n    @OneToOne\n    private Book book;\n    @OneToOne\n    private User user;\n    @JsonFormat(pattern = ("yyyy/MM/dd HH:mm:ss"))\n    @JsonSerialize(using = LocalDateTimeSerializer.class)\n    @JsonDeserialize(using = LocalDateTimeDeserializer.class)\n    private LocalDateTime dateOfRental;\n\n    public BookRentals(Book book, User user) {\n        this.book = book;\n        this.user = user;\n    }\n\n}\n

我这样设定时间：

private BookRentals …

我试图测试负责从文件中检索数据的方法。我想测试是否正确抛出异常。

   package contentfile;

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.stream.Stream;

public class ContentFileRetrieverService implements ContentFileRetriever {

    @Override
    public String[] getContentFile(String pathName) {

        Stream<String> contentFileStream;
        try {
            contentFileStream = Files.lines(Paths.get(pathName));
        } catch (IOException e) {
            throw new IllegalArgumentException(e);
        }

        return contentFileStream.toArray(String[]::new);
    }
}

我的测试：

package contentfile;

import org.junit.jupiter.api.Test;

import static org.junit.Assert.*;

class ContentFileRetrieverServiceTest {

    private ContentFileRetrieverService contentFileRetrieverService = new ContentFileRetrieverService();

    @Test
    void getContentFile() {
        String pathFile = "src\\test\\java\\resources\\TestText.txt";
        String[] testedContent = contentFileRetrieverService.getContentFile(pathFile);
        String[] expected = {"Line1 a", "Line2 b c", …

我是Spring Security的新人.如果我按下登录,则会发生以下网站:http:// localhost:8080/j_spring_security_check

HTTP Status 403 – Forbidden
Type Status Report

Message Forbidden

Description The server understood the request but refuses to authorize it.

Apache Tomcat/9.0.12

这是web.xml

<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            /WEB-INF/spring/webcontext/security-context.xml
        </param-value>
    </context-param>
    <listener>
        <listener-class>
            org.springframework.web.context.ContextLoaderListener
        </listener-class>
    </listener>
    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>
    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>
    <servlet>
        <servlet-name>DefaultServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring/webcontext/DispatcherServlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>DefaultServlet</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>
</web-app>

login.jsp 

在这里: <form action="<c:url value="/j_spring_security_check"></c:url>" method="post">- /j_spring_security_check标记在红色上并带有错误:Cannot resolve controller …

我尝试单元测试，如果方法负责返回给定产品的价格，如果我们通过坏抛出一个例外item_id- find_price_of_given_id。

测试：

import unittest
from Automat import Automat
from Bank import Bank
from Item import Item
from exceptions.NoItemException import NoItemException


class AutomatTest(unittest.TestCase):

    def test_checkPriceOfGivenID(self):
        bank = Bank()
        automat = Automat(bank)
        Cola = Item(2)
        automat.add_object(Cola)
        self.assertEqual(automat.find_price_of_given_id(30), 2)

    def test_checkPriceOfGivenIDWithInvalidID(self):
        bank = Bank()
        automat = Automat(bank)
        Cola = Item(2)
        automat.add_object(Cola)
        self.assertRaises(NoItemException, automat.find_price_of_given_id(31))

自动垫类：

if __name__ == '__main__':
    unittest.main()


from Item import Item
from exceptions.NoItemException import NoItemException
from exceptions.NoProperAmountException import NoProperAmountException
from Coin import Coin
from decimal import * …

我试图了解线程。我写了简单的程序。

public class Main {
    static int counter = 0;

    public static void main(String[] args) throws InterruptedException {
        Thread t1 = new Thread(() -> {
            for (int i = 0; i < 1000; i++) {
                counter++;
            }
        });
        Thread t2 = new Thread(() -> {
            for (int i = 0; i < 1000; i++) {
                counter++;
            }
        });

        t1.start();
        t2.start();
        t1.join();
        t2.join();
        System.out.println(counter);
    }
}

结果始终是2000，但是我不知道为什么。任何运行方法都不同步，所以为什么它总是给我相同的结果。

如果我写：

 t1.start();
        t1.join();
        System.out.println(counter);
        t2.start();
        System.out.println(counter);

然后我得到结果：1000,1000。为什么总是等于1000？

我正在尝试对负责从文本文件中检索数据的单元测试方法进行测试。

使用该方法的类如下所示：

package contentfile;

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.stream.Stream;

public class ContentFileRetrieverService implements ContentFileRetriever {

    @Override
    public String[] getContentFile(String pathName) {

        Stream<String> contentFileStream;
        try {
            contentFileStream = Files.lines(Paths.get(pathName));
        } catch (IOException e) {
            throw new IllegalArgumentException(e);
        }

        return contentFileStream.toArray(String[]::new);
    }
}

这是测试的样子：

package contentfile;

import org.junit.Rule;
import org.junit.jupiter.api.Test;

import static org.junit.Assert.*;

class ContentFileRetrieverServiceTest {

    private ContentFileRetrieverService contentFileRetrieverService;

//    @Rule
//    TemporaryFiles temporaryFiles = new TemporaryFiles();

    @Test
    void getContentFile() {
        String pathFile = "tekst.txt";
        String[] testedContent = contentFileRetrieverService.getContentFile(pathFile); …