这是我的代码:
(define step1_list1 '(1 3 (5 7) 9))
(car (cdr (cdr (step1_list1))))
(define step1_list2 '((7)))
(car (step1_list2))
(define step1_list3 '(1 (2 (3 (4 (5 (6 7)))))))
(car (cdr (cdr (cdr (cdr (cdr step1_list3))))))
))
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运行此代码会导致错误:
(1 3 (5 7) 9) is not applicable
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问题是什么?
scheme ×1