小编syn*_*012的帖子

我需要一些例子@@fetch_status值-2和-9

   0 = The FETCH statement was successful.
  -1 = The FETCH statement failed or the row was beyond the result set.

这是一个示例游标示例

 declare @country varchar(50)
 declare cur_country cursor for 
  select name from global
 open cur_country

fetch next from cur_country into @country
  print @@FETCH_STATUS
 while (@@FETCH_STATUS=0)
begin
insert into country select @country
fetch next from cur_country into @country
end

 close cur_country
 deallocate cur_country.

-2 提取的行丢失了. -9 游标未执行获取操作.

基本上需要@@FETCH_STATUS给出-20r的场景-9

我有一个这样的查询

SELECT COUNT(u.user_id) AS count1 FROM users WHERE user_id>1001 
UNION
SELECT COUNT(c.hits) AS count2 FROM source c WHERE loginid LIKE 'fb%';

结果

count1 
250
56

怎么能做成这样的单行

count1   count2
250      56

如果条件匹配,如何在一段时间间隔后更新表格？

tb_contest
id   contest_id   name   is_expire
1    101          new    0
2    102          old    0

tb_answer
contest_id   answer_id   date
101          1           2012-02-02
101          2           2012-09-14
102          5           2012-06-01

我需要tb_contest在满足某些条件后更新,并is_expire=1根据收到的最后一个答案在2天后进行更新:2012-03-14所以tb_contest应该更新2012-09-16.

我在 MYSQL 数据库中有一个名为 apps 的表。

我想要一个查询来提供总计数和fb计数