手头有以下代码:
ExecutorService executor = Executors.newFixedThreadPool(10);
Collection collection = new ArrayList();
for (int n=1; n<100; n++)
collection.add(new MyThread(n));
try {
List<Future<Boolean>> futures = executor.invokeAll(collection);
for(Future<Boolean> future : futures){
future.get();
if (future.isDone()) {
System.out.println("true");
}
else
System.out.println("false");
}
} catch (Exception e) {
e.printStackTrace();
}
如果以上是正确的？
如果一切future.isDone()都是真的,那么所有的线程都已经完成了吗？
我怎样才能制作旗帜,以确保所有这些都完成了？
例如,我有2个时间表:T1
id time
1 18:12:02
2 18:46:57
3 17:49:44
4 12:19:24
5 11:00:01
6 17:12:45
和T2
id time
1 18:13:02
2 17:46:57
我需要从T1获得与T2时间最接近的时间.这些表之间没有关系.它应该是这样的:
select T1.calldatetime
from T1, T2
where T1.calldatetime between
T2.calldatetime-(
select MIN(ABS(T2.calldatetime-T1.calldatetime))
from T2, T1)
and
T2.calldatetime+(
select MIN(ABS(T2.calldatetime-T1.calldatetime))
from T2, T1)
但我无法得到它.有什么建议？
我是java web应用程序开发的新手,你能告诉我,我做错了什么:我使用maven生成了web应用程序:
mvn archetype:generate -DgroupId=com.mycompany.app -DartifactId=webapp -DarchetypeArtifactId=maven-archetype-webapp
我把HelloWorld.java放在src.main.resources文件夹中,这里是代码:
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class HelloWorld extends HttpServlet{
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws ServletException,IOException{
response.setContentType("text/html");
PrintWriter pw = response.getWriter();
pw.println("<html>");
pw.println("<head><title>Hello World</title></title>");
pw.println("<body>");
pw.println("<h1>Hello World</h1>");
pw.println("</body></html>");
}
}
来自src.main.webapp.WEB-INF的我的web.xml如下所示:
!DOCTYPE web-app PUBLIC
"-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
"http://java.sun.com/dtd/web-app_2_3.dtd" >
<web-app>
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>Hello</servlet-name>
<servlet-class>HelloWorld</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Hello</servlet-name>
<url-pattern>/HelloWorld</url-pattern>
</servlet-mapping>
</web-app>
这是我的pom.xml:
project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/maven-v4_0_0.xsd">
<modelVersion>4.0.0</modelVersion> …我对SiftDescriptorExtractor工作的最后一部分有疑问,
我正在做以下事情:
SiftDescriptorExtractor extractor;
Mat descriptors_object;
extractor.compute( img_object, keypoints_object, descriptors_object );
现在我想检查一下descriptors_object Mat对象的元素:
std::cout<< descriptors_object.row(1) << std::endl;
输出看起来像:
[0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 3, 3, 0, 0, 0, 0, 0, 0, 32, 15, 0, 0, 0, 0, 0, 0, 73, 33, 11, 0, 0, 0, 0, 0, 0, 5, 114, 1, 0, 0, 0, 0, 51, 154, 20, 0, 0, 0, 0, 0, 154, 154, 1, 2, 1, 0, 0, 0, …我已经创建了Web浏览器,现在我想通过单击表单上的button1单击Web上的按钮.
private void button1_Click(object sender, EventArgs e)
{
webBrowser1.Document.GetElementById("search").SetAttribute("value", IP.Text);
webBrowser1.Document.GetElementById("").InvokeMember("click");
}
但我无法从此字符串中获取按钮ID
<input type="submit" value="?" class="button">
有没有办法解决这个问题？
svg 字体有问题。
这是我的index.html
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
</head>
<body>
<img src="sign.svg"></img>
</body>
</html>
这是我的 svg 文件
<?xml version="1.0" encoding="utf-8"?>
<!-- Generator: Adobe Illustrator 18.0.0, SVG Export Plug-In . SVG Version: 6.00 Build 0) -->
<!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.1//EN" "http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd">
<svg version="1.1" id="Layer_1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px"
viewBox="0 47.2 110 20.6" enable-background="new 0 47.2 110 20.6" xml:space="preserve">
<defs>
<style type="text/css">
@font-face {
font-family: 'Indie Flower';
font-style: normal;
font-weight: 400;
src: url('http://fonts.gstatic.com/s/indieflower/v7/10JVD_humAd5zP2yrFqw6qRDOzjiPcYnFooOUGCOsRk.woff') format('woff');
} …