所以我正在搞乱twitter api,我希望将这个文件包含在每个页面的页脚中.页脚通过phps require_once函数加载.问题是我无法使用完整的URL,因为url文件acsess因为显而易见的原因被关闭.所以我试着用
require_once $_SERVER['DOCUMENT_ROOT']('/lib/twitter/base.php');
Run Code Online (Sandbox Code Playgroud)
但那失败了.我做错了什么或者我怎样才能做得更好?
tableOk所以我想做的是以下内容
我在mysql中的一个数据库上有多个表
数据库1
table1
table2
table3
table4
table5
Run Code Online (Sandbox Code Playgroud)
每个表都有一个列id
对于匹配的每个id,我想删除该行.所以删除每个表中的954001行.在不杀死我的数据库的情况下,最好的方法是什么.顺便说一句,所有的ID都是全面匹配的.
<?php
// get value of id that sent from address bar
$customer_id=$_GET['id'];
$id=$_GET['id'];
// Delete data in mysql from row that has this id
$sql="DELETE FROM teable_users WHERE customer_id = $customer_id;
DELETE FROM table_parties WHERE id = $id;
DELETE FROM table_weddings WHERE id = $id;
DELETE FROM table WHERE id = $id;
DELETE FROM table_request_client WHERE id = $id;
DELETE FROM table_requests WHERE id = $id;
DELETE FROM table_users WHERE …Run Code Online (Sandbox Code Playgroud) 好的,我想要发生的是当用户注销时我的脚本应该检查代码2的URL并向用户显示他们已经注销.如果1有密码或用户名错误,3不确定他们是如何到达那里的.它拉出正确的数字,但只显示1的消息.我不知道什么是错的:/
<?php
$err = $_GET['err'];
echo $err;//Proof the code is getting number
if ($err = "1") {
echo '<center><span class="error-box">'; echo "Whoops! Wrong Username or Password. Please try again.</span></center>";
}
elseif ($err = '2') {
echo '<center><span class="info-box">'; echo "You Have Been Succesfully Logged Out.</span></center>";
}
else {
echo '<center><span class="info-box">'; echo "Whoops! Somthing funny happened and were not quite sure what your trying to do. Please try again.</span></center>";
}
?>
Run Code Online (Sandbox Code Playgroud)