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PHPStorm FTP连接失败

嘿我在PHPstorm中连接FTP时遇到问题.我知道我有正确的参数,因为它适用于其他FTP客户端.

我得到的错误是:无法列出文件夹" ftp://real-meal.com/ "的内容

端口设置为21,应该是.我知道我有正确的用户名/密码.任何想法可能是什么问题?

这是日志文件:

    2013-08-22 14:31:40,053 [8689769]   INFO - api.vfs.impl.local.FileWatcher - Change requests:38912, filtered:15503 
2013-08-22 14:35:55,090 [8944806]   INFO - api.vfs.impl.local.FileWatcher - Change requests:39936, filtered:15933 
2013-08-22 14:36:12,356 [8962072]   WARN - i.remotebrowser.ServerTreeNode - Could not list the contents of folder "ftp://real-meal.com/". 
org.apache.commons.vfs2.FileSystemException: Could not list the contents of folder "ftp://real-meal.com/".
    at org.apache.commons.vfs2.provider.AbstractFileObject.getChildren(AbstractFileObject.java:926)
    at org.apache.commons.vfs2.provider.ftp.FtpFileObject.getChildren(FtpFileObject.java:443)
    at org.apache.commons.vfs2.provider.AbstractFileObject.getChild(AbstractFileObject.java:1006)
    at com.jetbrains.plugins.webDeployment.connections.RemoteConnectionPool.createConnection(RemoteConnectionPool.java:124)
    at com.jetbrains.plugins.webDeployment.connections.RemoteConnectionManager.openConnection(RemoteConnectionManager.java:122)
    at com.jetbrains.plugins.webDeployment.ui.remotebrowser.ServerTreeContext.getConnection(ServerTreeContext.java:83)
    at com.jetbrains.plugins.webDeployment.ui.remotebrowser.ServerTreeNode.computeFile(ServerTreeNode.java:266)
    at com.jetbrains.plugins.webDeployment.ui.remotebrowser.ServerTreeNode.getChildren(ServerTreeNode.java:132)
    at com.intellij.ui.treeStructure.SimpleTreeStructure.getChildElements(SimpleTreeStructure.java:25)
    at com.intellij.ide.util.treeView.AbstractTreeUi$31.run(AbstractTreeUi.java:1618)
    at com.intellij.ide.util.treeView.AbstractTreeUi.execute(AbstractTreeUi.java:1824)
    at com.intellij.ide.util.treeView.AbstractTreeUi.getChildrenFor(AbstractTreeUi.java:1615)
    at com.intellij.ide.util.treeView.AbstractTreeUi.access$4600(AbstractTreeUi.java:60)
    at com.intellij.ide.util.treeView.AbstractTreeUi$46.run(AbstractTreeUi.java:2702)
    at com.intellij.ide.util.treeView.AbstractTreeUi.execute(AbstractTreeUi.java:1824) …
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ftp phpstorm

21
推荐指数
2
解决办法
3万
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MySQL GROUP BY 不必要地使用临时?

我正在尝试优化查询。使用EXPLAIN告诉我它是Using temporary。考虑到表的大小(20m+ 条记录),这确实是低效的。查看 MySQL 文档内部临时表,我没有看到任何暗示在我的查询中需要临时表的内容。我还尝试将 ORDER BY 设置为与 GROUP BY 相同,但仍然说使用临时和查询需要永远运行。我正在使用 MySQL 5.7。

有没有办法避免为此查询使用临时表:

SELECT url,count(*) as sum 
FROM `digital_pageviews` as `dp` 
WHERE `publisher_uuid` = '8b83120e-3e19-4c34-8556-7b710bd7b812' 
GROUP BY url 
ORDER BY NULL;
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这是我的表架构:

create table digital_pageviews
(
  id             int unsigned auto_increment
    primary key,
  visitor_uuid   char(36)            null,
  publisher_uuid char(36) default '' not null,
  property_uuid  char(36)            null,
  ip_address     char(15)            not null,
  referrer       text                null,
  url_delete     text                null,
  url            varchar(255)        null,
  url_tmp        varchar(255)        null,
  meta           text                null, …
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mysql explain

2
推荐指数
1
解决办法
68
查看次数

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