我正在尝试实现类型编写器动画,以便在我使用之间给出行间距
function splitLetters(word) {
var content = word.innerHTML;
word.innerHTML ='';
var letters = [];
for (var i = 0; i < content.length; i++) {
var letter = document.createElement('span');
letter.className = 'letter';
var char = content.charAt(i);
letter.innerHTML = char===" "?" ":char;
word.appendChild(letter);
letters.push(letter);
}
wordArray.push(letters);
}
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letter.innerHTML = char ===""?"":char;
以同样的方式,我想给换行而不是 可能的方式?
让我们假设我想要显示一条线
伟大的网络开发者
现在我希望它以这种格式显示
great web
developer
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开发者之前,伟大的网络和网络中断之间的空间.
任何帮助将不胜感激.另外,我不希望言语像两个词一样精彩地吐出来.
var words = document.getElementsByClassName('word');
var wordArray = [];
var currentWord = 0;
for (var i = 0; i < words.length; i++) …Run Code Online (Sandbox Code Playgroud)我正在尝试构建一个用于识别七段显示的OCR,如下所述
使用开放式CV的预处理工具我在这里得到它
现在我正在尝试按照本教程 - https://www.pyimagesearch.com/2017/02/13/recognizing-digits-with-opencv-and-python/
但就此而言
digitCnts = contours.sort_contours(digitCnts,
method="left-to-right")[0]
digits = []
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我收到错误 -
使用THRESH_BINARY_INV解决了错误,但仍然没有OCR工作任何修复都会很好
文件"/Users/ms/anaconda3/lib/python3.6/site-packages/imutils/contours.py",第25行,在sort_contours中key = lambda b:b 1 [i],reverse = reverse))
ValueError:没有足够的值来解包(预期2,得到0)
任何想法如何解决这个问题,让我的OCR成为一个有效的模型
我的整个代码是:
import numpy as np
import cv2
import imutils
# import the necessary packages
from imutils.perspective import four_point_transform
from imutils import contours
import imutils
import cv2
# define the dictionary of digit segments so we can identify
# each digit on the thermostat
DIGITS_LOOKUP = {
(1, 1, 1, 0, 1, 1, 1): 0, …Run Code Online (Sandbox Code Playgroud) 我正在尝试使用plotly为单个图中的多个数据帧绘制折线图。我的代码是:
import plotly.express as px
labels=category_names[:10]
for category in category_names[:10]:
df_b=df1[df1['Country/Region']==category]
fig=px.line(df_b, x="Date", y="Confirmed",labels="Country/Region")
print(category)
fig.show()
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但是,通过使用上面的代码,我只能获取 for 循环最后一次迭代的线图。
电流输出:
期望的输出:
请帮助我的代码!
我在 python 上的任何地方都有一个文件结构:
烧瓶主机(文件夹),其中包含:
app.py 包含 -:
import flask
from flask import request, jsonify
import sqlite3
app = flask.Flask(__name__)
app.config["DEBUG"] = True
def dict_factory(cursor, row):
d = {}
for idx, col in enumerate(cursor.description):
d[col[0]] = row[idx]
return d
@app.route('/', methods=['GET'])
def home():
return '''<h1>Distant Reading Archive</h1>
<p>A prototype API for distant reading of science fiction novels.</p>'''
@app.route('/api/v1/resources/books/all', methods=['GET'])
def api_all():
conn = sqlite3.connect('books.db')
conn.row_factory = dict_factory
cur = conn.cursor()
all_books = cur.execute('SELECT * FROM books;').fetchall()
return jsonify(all_books)
@app.errorhandler(404) …Run Code Online (Sandbox Code Playgroud) var input = document.getElementById("search");
function showTrue() {
document.getElementById("output").innerHTML = "It's true";
}
function showFalse() {
document.getElementById("output").innerHTML = "It's false";
}
// Get the input field
// Execute a function when the user releases a key on the keyboard
input.addEventListener("keyup", function(event) {
// Cancel the default action, if needed
event.preventDefault();
// Number 13 is the "Enter" key on the keyboard
if (event.keyCode === 13) {
// Trigger the button element with a click
showFalse();
}
});Run Code Online (Sandbox Code Playgroud)
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; …Run Code Online (Sandbox Code Playgroud)