我正在尝试生成一个与初始文件几乎相同的 xml 文件,但我需要我的 xsl 表将其转换为仅包含那些具有“公寓”或“单元”的 <类型> 并具有值的文件< numberofBedrooms > 中超过 1 个我完全迷失了,任何帮助将不胜感激!
我的初始 xml 表如下:
<rentalProperties>
<property available="yes" contact="0423020892">
<type>house</type>
<price>800</price>
<address>
<streetNo>116</streetNo>
<street>Warrigal Road</street>
<suburb>Camberwell</suburb>
<state>VIC</state>
<zipcode>3124</zipcode>
</address>
<numberOfBedrooms>4</numberOfBedrooms>
<description>Ideal for the familly is this charming Californian Bungalow. Comprising a spacious living area, formal dining room plus a huge family/meals area, bright modern well appointed kitchen with dishwasher, gas cooktop and electric oven and heaps of bench space, Four double bedrooms, two in a wing of their own, are …Run Code Online (Sandbox Code Playgroud)