我正在尝试使用css和html在div容器中插入图像,但它不显示任何图像.
HTML代码:
<div id="wrapper">
<div id="quoteContainer">
<span class="start_img"></span>
</div>
</div>
CSS:
#quoteContainer {
color: #898989;
background:#F9F9F9;
border: solid 1px #ddd;
border-radius:10px;
-moz-border-radius: 10px;
-webkit-border-radius: 10px;
box-shadow: 0px 0px 10px #888;
-moz-box-shadow: 0px 0px 10px #888;
-webkit-box-shadow: 0px 0px 10px #888;
margin:65px auto;
padding:15px;
width:500px;
}
.start_img {
background: url(image/img1.png);
border: dotted 2px black;
width:200px;
height:20px;
}
除了img,甚至没有边界表演.我尝试<img>在html中使用标记将图像插入div中,这也不起作用.代码有什么问题吗？
我有一个表格,将书籍信息插入数据库.但是它没有读取$ _POST属性.
book.php中:
<form action="books_manage.php" id="addbook_form" method="post">
<div id="ab_wrapper">
<div id="ab_leftcolumn">
<div id="bookinfo">
<fieldset>
<legend>Book Details</legend>
<div class="field">
<label>Book ID</label>
<input type="text" name="bid" id="bid"/>
</div>
<div class="field">
<label>Name</label>
<input type="text" name="bname" id="bname"/>
</div>
<div class="field">
<label>Author</label>
<input type="text" name="bauthor" id="bauthor"/>
</div>
<div class="field">
<label>Info</label>
<textarea name="binfo" id="binfo" cols="5" rows="5" ></textarea>
</div>
<div class="field">
<label>Date Added</label>
<input type="text" value="<?php echo date('D d M Y')?>" name="bdateadd" id="bdateadd"/>
</div>
<div class="field">
<label>Date Updated</label>
<input type="text" value="<?php echo date("D d M Y")?>" name="bdateupd" id="bdateupd"/> …我如何检查使用php dom,如果存在xml文件,如果没有创建它.
<?php
header("Location: index.php");
$xmldoc = new DOMDocument();
$xmldoc->load('sample.xml');
$newAct = $_POST['activity'];
$root = $xmldoc->firstChild;
$newElement = $xmldoc->createElement('activity');
$root->appendChild($newElement);
$newText = $xmldoc->createTextNode($newAct);
$newElement->appendChild($newText);
$xmldoc->save('sample.xml');
?>
现在,因为它不存在,它给了我这个错误:
DOMDocument::load(): I/O warning : failed to load external entity
how do i check in xml [with php dom] that if a particular element exists, it should not repeat it. for example, if i have an element 'activity', it should check against the xml file if this element exists, and if it does, it will not create it again.
in other words, i would like to create the element 'activity' only once in the beginning, but the other elements can be recurring.
this is the php code:
<?php
header("Location: index.php"); …我有这个xml代码:
<title xml:lang="ar">?????</title>
<title xml:lang="en">English</title>
我在xsl格式化:
<div class="title">
<xsl:value-of select="root/title"/>
</div>
然而,这^只显示阿拉伯语标题,而不是英语标题.我试过这段代码:
<div class="title">
<xsl:attribute name="xml:lang"><xsl:value-of select="root/title"/> </xsl:attribute>
</div>
但是使用这个^代码,它根本不显示标题.显示英语和阿拉伯语标题的正确方法是什么？
如何将月份字符串转换为整数？
在点击方法中,我想显示所选的日期,但如果日期有事件,则应显示有关该事件的更多信息.检查假日事件的方法需要整数值.
这是代码:
更新:
@Override
public void onClick(View view)
{
int m = 0;
int d, y;
String date_month_year = (String) view.getTag();
selectedDayMonthYearButton.setText("Selected: " + date_month_year);
String [] dateAr = date_month_year.split("-");
Log.d(tag, "Date Split: " + dateAr[0] + " " + dateAr[1] + " " + dateAr[2]);
y = Integer.parseInt(dateAr[2]);
try {
Calendar c1 = Calendar.getInstance();
c1.setTime(new SimpleDateFormat("MMM").parse(dateAr[1]));
m = c1.get((Calendar.MONTH) + 1);
}
catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
//int m = Integer.parseInt(dateAr[1]);
d …由于jquery,由于某些奇怪的原因,我收到错误"对象预期",并且这不会"提交"表单或将数据输入数据库.
没有jquery,数据可以输入数据库.但现在却没有.
我使用jquery主要用于验证asp.net控件.
roosteronacid,验证工作完全正常,id属性也相同.提交只是没有执行服务器端代码,我无法弄清楚是什么问题.
编辑:
这是jquery代码:
<script type="text/javascript">
$(document).ready(function() {
// add custom validation methods
$.validator.addMethod('phone', function(value, el, params) {
return this.optional(el) || /^[0-9,+,(), ,]{1,}(,[0-9]+){0,}$/.test(value);
}, 'Please enter a valid phone number');
$.validator.addMethod('numbers', function(value, el, params) {
return this.optional(el) || /^[0-9]+$/.test(value);
}, 'Invalid entry. Only Numeric is allowed.');
$.validator.addMethod('domainurl', function(value, el, params) {
return this.optional(el) || /^(http\:\/\/(?:www\.)?[a-zA-Z0-9]+(?:(?:\-|_)[a-zA-Z0-9]+)*(?:\.[a-zA-Z0-9]+(?:(?:\-|_)[a-zA-Z0-9]+)*)*\.[a-zA-Z]{2,4}(?:\/)?)$/.test(value);
}, 'Please enter a valid domain url');
$.validator.addMethod('selectone', function(value, element) {
return this.optional(element) || (value.indexOf("none") == -1);
}, 'Please select an option.');
$("#form1").validate({ …我正在尝试学习php/mysql.
将数据插入mysql工作正常,但插入带有撇号的数据会产生错误.我尝试使用mysql_real_escape_string,但这不起作用.
非常感谢任何帮助.
<?php
include 'config.php';
echo "Connected <br />";
$auth = $_POST['author'];
$quo = $_POST['quote'];
$author = mysql_real_escape_string($auth);
$quote = mysql_real_escape_string($quo);
//**************************
//inserting data
$sql="INSERT INTO Quotes (vauthor, cquotes)
VALUES ($author, $quote)";
if (!mysql_query($sql,$conn))
{
die('Error: ' . mysql_error());
}
echo "1 record added";
...
我究竟做错了什么？
在sql表中有一个id,名字和姓氏字段.我想连接第一个和最后一个名称字段,并在下拉控件中将其显示为一个.
这是vb.net代码:
con()
sqry = "[SELECT QUERY]"
sqcom = New SqlCommand(sqry, sqcon)
da.SelectCommand = sqcom
ds.Clear()
da.Fill(ds)
ddl_adv.DataSource = ds
ddl_adv.DataTextField = "emp_fname"
ddl_adv.DataValueField = "emp_no"
ddl_adv.DataBind()
sqcon.Close()
^此代码仅显示名字.我如何在asp.net中连接？
我有一个表单,我想在其中使用jQuery检索文本框中的值.问题是如果我声明这样的变量:
var bdmm = $("#bdmm").val();
在document.ready事件中,但在函数外部,并在函数中引用它,文本值为null.但是,如果我在函数内声明它,它工作正常.为什么会这样？
JQUERY:
这将不工作:
$(document).ready(function() {
var bdmm = $("#bdmm").val();
$('#submit').click(function(e){
alert(bdmm);
e.preventDefault();
});
});
这将有效:
$(document).ready(function() {
$('#submit').click(function(e){
alert($("#bdmm").val());
e.preventDefault();
//OR
var bdmm = $("#bdmm").val();
alert(bdmm);
e.preventDefault();
});
});
在我的Hijri日历应用程序中,如果我点击下个月按钮并到达年底(即上个月)或者如果我点击"上个月"按钮直到我到达年初(即第一个月) ,应用程序崩溃和抛出 java.lang.ArrayIndexOutOfBoundsException
private ImageView calendarToJournalButton;
private Button selectedDayMonthYearButton;
private final String[] hmonths = {"Muharram", "Safar", "Rabi al-Awwal", "Rabi al-Akhir", "Jamadi al-Awwal", "Jamadi al-Akhir", "Rajab", "Shabaan", "Ramadhan", "Shawwal", "Zilqad", "Zilhajj"};
private Button currentMonth;
private ImageView prevMonth;
private ImageView nextMonth;
private GridView calendarView;
private GridCellAdapter adapter;
private Calendar _calendar;
private int month, year, hmonth, hyear;
private final DateFormat dateFormatter = new DateFormat();
private static final String dateTemplate = "MMMM yyyy";
private String hmonthname;
private HijriCalendar hijri;
/** Called when the activity …我想将单选按钮显示为选项卡。遵循此codepen，我在我的项目中尝试了这一点。但是当我单击伪选项卡时，什么也没有发生。它没有得到checked。
怎样才能达到效果呢？
input.tgl-radio-tab-child {
position: absolute;
left: -99999em;
top: -99999em;
opacity: 1;
z-index: 1;
}
input.tgl-radio-tab-child+label {
cursor: pointer;
float: left;
border: 1px solid #aaa;
margin-right: -1px;
padding: .5em 1em;
position: relative;
}
input.tgl-radio-tab-child+label:hover {
background-color: #eee;
}
[type=radio]:checked+label {
background-color: #c30;
z-index: 1;
}<label for="abc">ABC<span style="color: red;">*</span></label>
<div class="form-check">
<div class="tgl-radio-tabs">
<input type="radio" class="form-check-input tgl-radio-tab-child" name="abcorigin"><label class="radio-inline">ABCDEFGHIJKL</label>
<input type="radio" class="form-check-input tgl-radio-tab-child" name="abcorigin"><label class="radio-inline">MNOPQRSTUVWXYZ</label>
</div>
</div>