我搜索了类似的主题,但找不到清晰简洁的答案。我一直在尝试找出一种方法,可以确定在播放Android媒体播放器时在给定时间点的分贝级别输出。我无法找到一种方法来确定在播放歌曲时给定时间点手机的声音大小。我一直在寻找媒体播放器API,但无法弄清楚在播放歌曲时如何在给定的时间阅读。
任何想法或帮助表示赞赏。
我正在尝试实现Android Visualizer类.我已查找其他麻烦线程,但我仍然遇到致命错误.这一切在我看来它应该正常工作,无论出于何种原因AVD继续崩溃.
首先,我正在使用权限:
<uses-permission android:name="android.permission.RECORD_AUDIO" />
<uses-permission android:name="android.permission.MODIFY_AUDIO_SETTINGS"/>
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这是我的logcat:
12-21 15:10:46.983: D/dalvikvm(642): Not late-enabling CheckJNI (already on)
12-21 15:10:48.823: D/MediaPlayer(642): Couldn't open file on client side, trying server side
12-21 15:10:53.603: E/AudioEffect(642): set(): AudioFlinger could not create effect, status: -22
12-21 15:10:53.603: E/visualizers-JNI(642): Visualizer initCheck failed -4
12-21 15:10:53.613: E/Visualizer-JAVA(642): Error code -4 when initializing Visualizer.
12-21 15:10:53.613: E/Visual Ex(642): Cannot initialize Visualizer engine, error: -4
12-21 15:10:53.964: D/gralloc_goldfish(642): Emulator without GPU emulation detected.
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我的代码:
package MediaPlayer.namespace;
import java.io.IOException;
import …Run Code Online (Sandbox Code Playgroud) 我试图在PHP中显示一个表.我已经建立了有效的连接.我收到错误:
Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING in /Applications/XAMPP/xamppfiles/htdocs/project.php on line 17
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页面代码:
<html>
<head>
<title>PHP Site Michael Mazur</title>
</head>
<body>
<?php
//connect to DB
$con=mysql_connect("localhost","mike","mike");
$db_found = mysql_select_db("my_guitar_shop2");
$result = mysql_query("SELECT firstName,lastName FROM customers");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['firstName'] . "</td>";
echo "<td>" . $row['lastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
</body>
</html>
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