这是另一个"for xml"问题,但我不确定这是否可以在没有显式模式的情况下完成.如果它不能,那么我将不得不忍受它.
以下是我目前的select语句:
SELECT
[stream_id] as '@stream_id',
[path_locator] as '@path_locator',
[parent_path_locator] as '@parent_path_locatr',
[file_type] as '@file_type',
[cached_file_size] as '@cached_file_size',
[creation_time] as '@creation_time',
[last_write_time] as '@last_write_time',
[last_access_time] as '@last_access_time',
[is_directory] as '@is_directory',
[is_offline] as '@is_offline',
[is_hidden] as '@is_hidden',
[is_readonly] as '@is_readonly',
[is_archive] as '@is_archive',
[is_system] as '@is_system',
[is_temporary] as '@is_temporary',
[name] as '/name',
dbo.udf_GetChildren(path_locator)
FROM @Merged
WHERE path_locator.GetLevel() = 1
FOR XML PATH'file'), ROOT('files'), TYPE
这将输出以下xml:
<files>
<file stream_id="" etc...>
<name>NAME</name>
</file>
</files>
这不错,但我真正喜欢的是将name元素的值作为file元素的值.这是一个如此简单的任务我认为它可以在没有显式模式的情况下完成,但我经常对这些事情做错.
我已经尝试使用'/'标记,但这似乎没有我想要的效果(例如SQL Server …