我的任务是将 Objective-C 应用程序转换为完全 Swift 4。该应用程序基本上是一个包含我公司网站的网络浏览器。为了让用户表单抱怨每次输入用户名/密码，应用程序需要检查何时提交 HTML 表单并抓取网站并存储 u/p。
ObjC中有一个方法：
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType
这使我可以检查表单何时提交：
static NSString * const FORM_USER = @"document.getElementById('sUserID').value";
static NSString * const FORM_PASS = @"document.getElementById('sPassword').value";
- (BOOL)webView:(UIWebView *)webView shouldStartLoadWithRequest:(NSURLRequest *)request navigationType:(UIWebViewNavigationType)navigationType {
//save form data
if(navigationType == UIWebViewNavigationTypeFormSubmitted) {
dispatch_async(dispatch_get_main_queue(), ^{
//grab the data from the page
NSString *username = [self.webView stringByEvaluatingJavaScriptFromString: FORM_USER];
NSString *password = [self.webView stringByEvaluatingJavaScriptFromString: FORM_PASS];
//store values locally in the background
//.....
});
}
return true;
}
但我在转换 Swift 4.1 时遇到了麻烦，因为我似乎找不到 …
直到第13个字符被击中为止.一旦str_ireplace在cyper数组中命中"a",str_ireplace就会停止工作.
数组的大小是否有限制？请记住,如果键入"abgf",我会得到"nots",但如果我输入"abgrf",当我得到"注释"时,我会得到"notrs".我的大脑无法弄明白.
$_cypher = array("n","o","p","q","r","s","t","u","v","w","x","y","z","a","b","c","d","e","f","g","h","i","j","k","l","m");
$_needle = array("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z");
$_decryptedText = str_ireplace($_cypher, $_needle, $_text);
echo $_decryptedText;
救命？
我有一个UIButton,它不仅出现在iOS 9.3中.
我不明白为什么.谁能告诉我我做错了什么？
我需要ViewDidAppear方法中的按钮,因为我在设置此按钮后需要放置一些其他布局元素.
iPhone 6 8.1按钮设置位置:{{100,100},{42,42}}
iPhone 6 9.3按钮设置位置:{{0,0},{0,0}}
iPhone 6Plus 8.1按钮设置位置:{{100,100},{42,42}}
iPhone 6Plus 9.3按钮设置位置:{{0,0},{0,0}}
#define MARGIN_SIZE 10
@interface HomeViewController ()
@property (weak, nonatomic) UIButton *btnSettings;
@end
- (void) viewDidAppear:(BOOL)animated {
[super viewDidAppear:animated];
self.btnSettings = [UIButton buttonWithType:UIButtonTypeCustom];
self.btnSettings.userInteractionEnabled = YES;
self.btnSettings.frame = CGRectMake(100, 100, 42, 42);
self.btnSettings.tag = 21;
[self.btnSettings setImage:[UIImage imageNamed:@"settings_black"] forState:UIControlStateNormal];
[self.btnSettings addTarget:self action:@selector(buttonPressed:) forControlEvents:UIControlEventTouchUpInside];
[self.view addSubview:self.btnSettings];
NSLog(@"Button Settings Location: %@", NSStringFromCGRect(self.btnSettings.frame) );
}
我有一个需要一些自定义 js 和样式的部分子视图。这个子视图是整个应用程序中唯一使用它的视图。它很复杂，所以 JS 被分解成它自己的文件。
我试图根据文档将脚本和样式“注入”到父布局中，但它似乎不起作用。我已经厌倦了@parent和@@parent部分的组合。我尝试将主要布局更改@yield('scripts') @yield('styles')为@section('scripts')@show.
我错过了什么？这甚至可能吗？
main.blade.php （为简洁起见缩短）
<head>
@include('apps.includes.styles')
@yield('styles')//a place for custom style
</head>
<body>
@yield('content')
@include('apps.includes.scripts')
@yield('scripts') //a place for custom scripts
</body>
创建.blade.php
@extends('layouts.main')
@section('styles')@endsection
@section('scripts')@endsection
@section('content')
<div>
@include('partials._toolbar')
</div>
@endsection
_toolbar.blade.php
@section('styles')
@parent
<script src="{{asset('assets/css/mystyle.css')}}"></script>
@endsection
@section('scripts')
@parent
<script src="{{asset('assets/js/myjs.js')}}"></script>
@endsection
<section>
// my toolbar html code
</section>