如何使用C#将"ThisIsMyTestString"转换为"This Is My Test String"?
有快速的方法吗?
我一直在想一个伪代码,但它复杂而丑陋:
String s = "ThisIsMyTestString";
List<String> strList = new List<String>();
for(int i=0; i < str->Length ; i++)
{
String tmp = "";
if (Char.IsUpper(str[i]))
{
tmp += str[i];
i++;
}
while (Char::IsLower(str[i]))
{
tmp += str[i];
i++;
}
strList .Add(tmp);
}
String tmp2 = "";
for (uint i=0 ; i<strList.Count(); i++)
{
tmp2 += strList[i] + " ";
}
Run Code Online (Sandbox Code Playgroud) 有人可以向我解释这个'构造函数'定义的优点是什么:
var Tree = (function () {
function Tree(name) {
this.name = name;
}
return Tree;
})();
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代替
var Tree = function(name) {
this.name = name;
};
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第一个变体由TypeScript编译器生成.
我正在尝试基于表单的身份验证,但是我不知道为什么,在登录页面上输入正确的用户名/密码后,它将重定向我到错误页面而不是index.jsp。
当我输入:
http://localhost:8080/<context>/secure/index.jsp
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我得到登录页面。但是,当我输入用户名/密码(manager / manager)时,它将带我到error.html而不是index.jsp。
WEB.XML:
<?xml version="1.0" encoding="UTF-8"?>
<web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<display-name>FormBasedAuthentication</display-name>
<login-config>
<auth-method>FORM</auth-method>
<form-login-config>
<form-login-page>/login.html</form-login-page>
<form-error-page>/error.html</form-error-page>
</form-login-config>
</login-config>
<security-role>
<role-name>role1</role-name>
</security-role>
<security-constraint>
<web-resource-collection>
<web-resource-name>SecurePages</web-resource-name>
<description>Security constraint for JSP resources</description>
<url-pattern>/secure/*</url-pattern>
<http-method>POST</http-method>
<http-method>GET</http-method>
</web-resource-collection>
<auth-constraint>
<role-name>role1</role-name>
</auth-constraint>
<user-data-constraint>
<transport-guarantee>NONE</transport-guarantee>
</user-data-constraint>
</security-constraint>
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TOMCAT-USER.XML:
<tomcat-users>
<role rolename="manager-gui"/>
<role rolename="manager-script"/>
<role rolename="manager-status"/>
<role rolename="manager-jmx"/>
<role rolename="role1"/>
<user username="manager" password="manager" roles="role1"/>
</tomcat-users>
Run Code Online (Sandbox Code Playgroud) 我需要让我的应用程序自动连接到特定SSID的密码.我正在尝试这个,但这就是我得到的:
错误:
非静态方法addNetwork(WifiConfiguration)不能从静态上下文中引用
错误:
非静态方法enableNetwork(int,boolean)不能从静态上下文中引用
final WifiManager wifiManager = (WifiManager) MainActivity.this.getSystemService(Context.WIFI_SERVICE);
final WifiConfiguration config = new WifiConfiguration();
config.SSID = "\"xxx\"";
config.preSharedKey = "\"123\"";
if (!wifiManager.isWifiEnabled()){
wifiManager.setWifiEnabled(true);
int networkId = WifiManager.addNetwork(config);
WifiManager.enableNetwork(networkId, true);
}
Run Code Online (Sandbox Code Playgroud) 我正在使用Rocket设置Rust服务器,我正在尝试将它与JWT库一起使用.他们使用*ring*crate的不同版本,我在以下期间收到错误cargo build:
error: multiple packages link to native library `ring-asm`, but a native library can be linked only once
package `ring v0.12.1`
... which is depended on by `jsonwebtoken v4.0.1`
... which is depended on by `auther v0.1.0 (file:///home/drpytho/x/downloadble/auther)`
links to native library `ring-asm`
package `ring v0.11.0`
... which is depended on by `cookie v0.9.2`
... which is depended on by `rocket v0.3.6`
... which is depended on by `rocket_codegen v0.3.6`
... which is …Run Code Online (Sandbox Code Playgroud) 我正在使用 Apache POI 工作簿在 Java 中打开 Excel 文件(源),更改特定单元格中的数据,将工作簿保存到单独的文件,然后关闭工作簿(因为文档指出要关闭工作簿,甚至如果它是只读的)。
POI 每次都会更改源 Excel 文件中的数据。根据 POI 文档的建议,我尝试了几种不同的方法来防止这种情况发生,但这些方法都失败了。
这里有两种尝试,理论上应该可行,但实际上却行不通。
尝试 1 - 将源文件设置为只读
File file = new File("{path-to-existing-source-file}");
file.setReadOnly();
Workbook workbook = WorkbookFactory.create(file); // throws a FileNotFoundException
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“访问FileNotFoundException被拒绝”被抛出WorkbookFactory.create(file):
java.io.FileNotFoundException: {path-to-source-file-that-exists} (Access is denied)
at java.io.RandomAccessFile.open0(Native Method)
at java.io.RandomAccessFile.open(RandomAccessFile.java:316)
at java.io.RandomAccessFile.<init>(RandomAccessFile.java:243)
at org.apache.poi.poifs.nio.FileBackedDataSource.newSrcFile(FileBackedDataSource.java:158)
at org.apache.poi.poifs.nio.FileBackedDataSource.<init>(FileBackedDataSource.java:60)
at org.apache.poi.poifs.filesystem.POIFSFileSystem.<init>(POIFSFileSystem.java:224)
at org.apache.poi.poifs.filesystem.POIFSFileSystem.<init>(POIFSFileSystem.java:172)
at org.apache.poi.ss.usermodel.WorkbookFactory.create(WorkbookFactory.java:298)
at org.apache.poi.ss.usermodel.WorkbookFactory.create(WorkbookFactory.java:271)
at org.apache.poi.ss.usermodel.WorkbookFactory.create(WorkbookFactory.java:252)
at com.stackoverflow.MyClass(MyClass.java:71)
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源文件存在,并且它是有效的只读文件。
尝试 2 - 使用允许显式设置只读的 POI API 构造函数
File file = new File("{path-to-existing-source-file}");
Workbook …Run Code Online (Sandbox Code Playgroud) 我pydot用来在我的机器上保存图像文件,然后使用Image模块打开文件.但是,我收到错误Windows Photo viewer.无法打开图像,因为它已被删除或位于不可用的位置.这是不正确的,因为图像保存到我的桌面.
有时,随机地,图片确实被打开,但需要花费很多时间.为什么我会遇到这个问题?
我可以选择以任何格式保存图像.是否存在可以保存的图像格式,通过Python打开的时间相对较少,或者所有格式都需要同时进行?
我正在尝试编写正则表达式来从HTML源中提取URL列表href和anchor文本.该anchor文本可以是任意值.
HTML部分如下:
<div class="links"><a rel="nofollow" target="_blank" href="http://url1.com" class="get-all">URL1</a><a rel="nofollow" target="_blank" href="http://url2.com" class="get-all">This is Url-2</a><a rel="nofollow" target="_blank" href="http://url3.com" class="get-all">This is Url-3</a><a rel="nofollow" target="_blank" href="http://url4.com" class="get-all">Sweet URL 4</a></div>
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我尝试了以下正则表达式,但由于它在</a>标记之前抓取所有内容并失败,因此无法正常工作.
preg_match_('/<a rel="nofollow" target="_blank" href="(.*)" class="see-all">(.*)<\/a>/', $source , $website_array);
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提取我所需数据的正则表达式是什么?
如何使构造函数设置全局数组的长度?
我已经尝试了几种方法,没有成功.
例:
public Class{
public Class(int length){
double[] array = new double[length]; <- this is not global
L = length;
}
int L;
double[] array = new double[L]; <- this does not work
}
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我需要一个长度由Constructor确定的数组.
我正在完成本教程
http://www.1stwebdesigner.com/tutorials/infinite-scrolling-tutorial/
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它包含以下代码段:
<!--?php
$con = mysql_connect("localhost", "username", "password");
mysql_select_db("database_name");
$result = mysql_query("select SQL_CALC_FOUND_ROWS * from scroll_images order by id asc limit 12");
$row_object = mysql_query("Select Found_Rows() as rowcount");
$row_object = mysql_fetch_object($row_object);
$actual_row_count = $row_object--->rowcount;
?>
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这条线$actual_row_count = $row_object--->rowcount;让我困惑,该怎么--->rowcount办?当我在PHP中使用它时,我收到错误.
<?php
$sql_fetch = "SELECT * FROM articles ORDER BY time DESC limit 4;";
$dbresult = mysqli_query( $db, $sql_fetch );
$row_object = mysqli_query( $db, "Select Found_Rows() as rowcount" );
$row_object = mysqli_fetch_object( $row_object );
$actual_row_count = $row_object--->rowcount;
?> …Run Code Online (Sandbox Code Playgroud) java ×3
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android ×1
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apache-poi ×1
arrays ×1
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dependencies ×1
excel ×1
image ×1
java-ee ×1
javascript ×1
python ×1
regex ×1
rust ×1
rust-rocket ×1
servlets ×1
string ×1
typescript ×1
wifimanager ×1