我在这里有此代码:
$('.fa').hover(function(){
$('#hiddenStuff').show();
});
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当用户将鼠标悬停在该元素上时,会出现另一个元素,当您将鼠标悬停在.fa元素上时,如何使该元素消失?
我在这里有这个方法,它完全按照我的需要返回我的数据:
func getTestData() -> [Any]?
{
return [GradingData(lot: "lot", andColumns: "andColumns", SLAIssuedFinalGrading: true, SLAIssuedFinalGradingDate: "SLAIssuedFinalGradingDate", CityApprovalIssued: true, CityCommentReceived: false, GradingRepair: "GradingRepair", CurbStopRepair: "CurbStopRepair", SplashPadDownSpout: "SplashPadDownSpout", RYCBOtherRepairs: "RYCBOtherRepairs", Comments: "Comments", columnCamera: "", DepositReceived: false), GradingData(lot: "lot", andColumns: "andColumns2", SLAIssuedFinalGrading: false, SLAIssuedFinalGradingDate: "SLAIssuedFinalGradingDate", CityApprovalIssued: false, CityCommentReceived: false, GradingRepair: "GradingRepair", CurbStopRepair: "CurbStopRepair", SplashPadDownSpout: "SplashPadDownSpout", RYCBOtherRepairs: "RYCBOtherRepairs", Comments: "Comments", columnCamera: "", DepositReceived: false)]
}
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现在我正在尝试调用 API 并返回完全相同的结构:
func GetLandGradingData(_ community: String, completion: @escaping (_ result: [GradingData]) -> Void)
{
let escapedCommunity = community.addingPercentEncoding(withAllowedCharacters: CharacterSet.urlQueryAllowed) …Run Code Online (Sandbox Code Playgroud) 我试图冻结我的 html 表 (thead) 中的第一行,但是当我尝试以下 CSS 代码时:
table {
width: 100% !important;
}
thead, tbody {
display: block;
}
tr:after {
content: ' ';
display: block;
visibility: hidden;
clear: both;
}
thead th {
height: 30px;
}
tbody {
height: 500px;
overflow-y: auto;
}
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thead 与 tbody 的大小不同。tbody 是可滚动的,thead 处于固定位置,但不一样,tr 聚集在一起。这是我的 HTML:
<table id="MVCGridTable_Grid" class="table table-striped table-bordered">
<thead>
<tr>
<th>aaa</th>
<th>aaa</th>
<th>aaa</th>
<th>aaa</th>
<th>aaa</th>
</tr>
</thead>
<tbody>
<tr>
<td>
aaa
</td>
<td>
aaa
</td>
<td>
aaa
</td>
<td>
aaa
</td> …Run Code Online (Sandbox Code Playgroud) 我试图像这样运行mySQL插入语句:
function insertAppointment($connection, $id, $firstname, $lastname, $email, $phone, $date, $time){
$sql = "INSERT INTO `appointments` (firstname, lastname, email, phone, app_date, app_time) VALUES ('" . $id . "', '" . $firstname . "', '" . $lastname . "', '" . $email . "', " . $date . ", " . $time . ")";
$connection->query($sql);
}
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$ connection是我的连接字符串,这不是问题.我可以将它用于select语句,如下所示:
function getTakenDates($connection){
$query = mysqli_query($connection, "SELECT app_date, app_time FROM `appointments`");
$results = array();
while($row = mysqli_fetch_assoc($query)){
$results[] = $row;
}
return $results;
}
Run Code Online (Sandbox Code Playgroud) 我定义了这个数组:
string[] emailAddress = {};
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我想做的是将项目添加到这个数组中,如下所示:
emailAddress[] = de.Properties["mail"][0].ToString();
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我收到无法将字符串转换为数组错误。如何将项目添加到数组中?
我在这里有这个代码:
public double ProgressBar
{
get
{
return ((double)Completed / Progress);
}
}
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但是当两个值(已完成和进度)都为 0 时,它总是返回 NaN。
我也试过:
public double ProgressBar
{
get
{
return ((double)Completed / (double)Progress);
}
}
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相同的结果 NaN
我究竟做错了什么?
我正在尝试将项目添加到列表中:
List<string> newList = new List<string>();
foreach (var x in dbTimeSlots.Data)
{
newList.Add(x.id.ToString());
newList.Add(x.timeSlot + " - " + x.dateSlot);
}
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然而,当我只有40时,我的列表返回80个项目,这是因为id将是一个项目,时间和日期将是另一个项目,我需要它们作为一行,但每行应该有一个id对象和日期和时间对象.我希望这有道理,请帮助!!!!