我无法理解为什么这不起作用.我的表单上有两个字段,当我单击一个按钮时,另一个文本字段值将更改为该函数.我怎样才能让它发挥作用?
function calculate()
{
var odometerStart = parseFloat (document.getElementById('odometerStart').value);
var odometerEnd = parseFloat(document.getElementById('odometerEnd').value);
var distance = document.getElementById('distance');
var amount = document.getElementById('amount');
distance.value = odometerEnd - odometerStart;
}
var val = $("#taskentry").validate({
rules: {
tripDate: {required: true}
tripContact: {required: true}
odometerStart: {required: true}
}
});
Odometer: Start <input type="number" name="odometer[Start]" id="odometerStart" min="0" max="999999" placeholder="0" class="required"/><br/>
Odometer: End <input type="number" name="odometer[End]" id="odometerEnd" min="0" max="999999" placeholder="999999" class="required"/><br/>
Comments <textarea name="comments" id="comments" rows="2" cols="2"></textarea><br/>
Distance <input type="text" name="distance" id="distance" value="" placeholder="0.00"/><br/>
<input type="button" name="calculate" …Run Code Online (Sandbox Code Playgroud) 我有以下单选按钮:
<fieldset data-role="controlgroup" data-type="horizontal">
<legend>Business Type</legend>
<input type="radio" name="businessType" value="business" id="business" checked="checked"/>
<label for="business">Business</label>
<input type="radio" name="businessType" value="personal" id="personal"/>
<label for="personal">Personal</label>
</fieldset>
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我尝试使用这个jQuery来获取所选单选按钮的当前值,但即使我选择个人,我也会继续将'Business'作为值:
var idd = ($("input:radio[name=businessType]").val());
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谢谢
我试图寻找一个如何做到这一点的答案,但我似乎无法找到一个.我知道要在perl中找到操作系统名称,你可以使用
$^O
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但是在Linux和Solaris中,无论您使用的操作系统版本如何,它都将返回Solaris或Linux.我希望它显示为Solaris10或Solaris11.有没有办法得到这个?我知道你是否进入
uname -r
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您可以获取版本号(例如Solaris中的5.10).有关如何做到这一点的任何想法?
谢谢=)
我想使用mysql_real_escape_string阻止1 = 1,但不确定我是否正确,因为我仍然可以执行1 = 1.这是我的代码:
$memberId = mysql_real_escape_string($_GET["memberId"]);
$sql = "SELECT firstName, lastName, dateSent, message, messageId FROM member, message WHERE member.memberId = message.sentFromId AND message.inboxId=" . $memberId . " ORDER BY dateSent DESC;";
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谢谢
我创建了一个Survey.java类和一个SurveyTest.java JUnit测试.但我不确定如何测试Survey类中的列表.如何在JUnit测试中测试它们?
Survey.java
package com.jhaksurvey.model;
import java.util.List;
public class Survey {
private long id;
private String title;
private boolean active = true;
private List<Question> questions;
public Survey() {
}
public Survey(long id, String title) {
this.id=id;
this.title=title;
}
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public String getTitle() {
return title;
}
public void setTitle(String title) {
this.title = title;
}
public boolean isActive() {
return active;
}
public void setActive(boolean …Run Code Online (Sandbox Code Playgroud)