我遇到了一个有趣的现象,我的buttonset()所有按钮之间都有差距.显然我希望他们像在jquery演示中一样.
我的代码很有库存
HTML
<div style="float:right;" id="filter-button-bar">
<input type="radio" id="it_button" name="radio" class="filter-button" /><label for="it_button">Information</label>
<input type="radio" id="rev_button" name="radio" class="filter-button" /><label for="rev_button">Revenue</label>
<input type="radio" id="ent_button" name="radio" class="filter-button" /><label for="ent_button">Entertainment</label>
<input type="radio" id="sec_button" name="radio" class="filter-button" /><label for="sec_button">Security</label>
<input type="radio" id="asst_button" name="radio" class="filter-button" /><label for="asst_button">Assistants</label>
<input type="radio" id="all_button" name="radio" class="filter-button" checked="checked"/><label for="all_button">All</label>
</div>
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JS
$(function() {
$( "#filter-button-bar" ).buttonset();
$( ".filter-button" ).button({
icons: {
primary: "ui-icon-search"
}
});
});
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令人讨厌的是,当放入jsfiddle时,一切看起来都很棒.的jsfiddle
所以当我jsStringFormat()试图逃避JSON的特殊字符时,我遇到了一个有趣的问题.我正在使用jQuery datatables插件并对Coldfusion进行AJAX调用.
似乎正在发生的事情是jsStringFormat()正在逃避撇号角色并放入\'我的JSON.根据JSON规范,单撇号不需要转义,因此它会中断.
这是我的JSON返回的示例
{
"sEcho": 2,
"iTotalRecords": 659,
"iTotalDisplayRecords": 201,
"aaData": [
["516", "", "54d 7h 12m", "02- Revenue", "", "Assist in validating error in JCA provided Discount Commission report", "Received", "Work Request", "Jan 1, 2012"],
["616", "", "16d 7h 12m", "02- Revenue", "", "Order/Install new POS Terminal at Katie\'s Workstation", "In Progress", "Work Request", "Oct 31, 2011"],
["617", "", "15d 7h 12m", "02- Revenue", "", "Replace #6081 POS Printer at Kim\'s Desk", "Received", "Work …Run Code Online (Sandbox Code Playgroud) 我试图从当前时间减去10分钟,但我无法在我查找的文档中找到正确的语法
到目前为止我有这个
def deltaMinutes = 10
use(TimeCategory) {
def nowTime = new Date() - deltaMinutes.minutes
log.debug nowTime
}
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并在SmartThings IDE中获取此信息
java.lang.NullPointerException @ line 53
也许IDE不支持这个库?计算这个的下一个最佳方法是什么?
我正在使用一个简单的道具调用来改变jqueryui"切换"按钮(又名checkbox)的状态:
$("#completed_button").prop("checked", true);
功能上,复选框正在更改状态,脚本正常运行.不幸的是,它没有改变按钮的视觉状态.知道为什么它没有,我能做些什么才能做到这一点?
示例:中间位置是使用鼠标切换时的样子,右边是使用上述调用时会发生的情况.注意文本是如何正确的,但视觉突出显示不是.

我是一个非常大的n00b与javascript和jquery所以我在这里尽我所能.我从Stackmob查询返回JSON.我需要知道如何正确地得到name,distance,lat和lon从该JSON字符串,所以我可以在谷歌的API调用进一步上使用它们.
[
{
"name": "eBay",
"lat_long": {
"lon": -121.927551,
"lat": 37.29546,
"distance": 0.004635090828588474
},
"locations_id": "a3563711ebb44a088ae5ab2bd7ff2e0e"
},
{
"name": "Facebook",
"lat_long": {
"lon": -121.894955,
"lat": 37.339386,
"distance": 0.005523591746943001
},
"locations_id": "3fbee8e363bf4247b2e8ca0958c38f4e"
},
{
"name": "Yahoo",
"lat_long": {
"lon": -122.025159,
"lat": 37.417237,
"distance": 0.006310220058572611
},
"locations_id": "d0c568a6322f4a3b8d2fe30cba68f8f1"
},
{
"name": "Hewlett Packard",
"lat_long": {
"lon": -122.145989,
"lat": 37.415515,
"distance": 0.006312489443257717
},
"locations_id": "f03676c3469d4b978bfefcb2ab13790d"
},
{
"name": "Google",
"lat_long": {
"lon": -122.083979,
"lat": 37.421931, …Run Code Online (Sandbox Code Playgroud) jquery ×3
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