小编ded*_*bed的帖子

Shape.h

namespace Graphics {
    class Shape {
    public:
        virtual void Render(Point point) {};
    };
}

Rect.h

namespace Graphics {
    class Rect : public Shape {
    public:
        Rect(float x, float y);
        Rect();
        void setSize(float x, float y);
        virtual void Render(Point point);

    private:
        float sizeX;
        float sizeY;
    };
}

struct ShapePointPair {
    Shape shape;
    Point location;
};

像这样使用:

std::vector<Graphics::ShapePointPair> theShapes = theSurface.getList();

for(int i = 0; i < theShapes.size(); i++) {
    theShapes[i].shape.Render(theShapes[i].location);
}

这段代码最终会调用Shape::Render而不是Rect::Render

我假设这是因为它正在施放Rect到a Shape,但我不知道如何阻止它这样做.我试图通过重写 …

我想让我的代码更快地运行，以进行更多的迭代和运行。现在，我的代码太慢了，但是我不知道要更改什么来加速它。我首先编写了动力学的蒙特卡洛模拟，然后将其编辑为布朗运动模拟。我当前的代码无法处理10,000次运行，每次运行10,000次迭代。

import numpy as np
import matplotlib.pyplot as plt
import time
%matplotlib inline

runs = int(input("Enter number of runs: "))
N = int(input("Enter number of iterations per simulation: "))

y = 0
R = 10*1  # R is the rate value
t0 = time.time()
for y in range(runs):  # Run the simulation 'runs' times
    T = np.array([0])
    dt = 0
    x = 0.5  # sets values 
    X = np.array([x])
    t = 0
    i = 0

    while t < N:  # …

return; in a void function. What does it actually do?

void function() {
    if(x==NULL) {
        return;
    }
    else{
        /////
    }
}