这是我的messageResource声明
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www.springframework.org/schema/p"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.2.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd">
<!-- Auto-detect controllers in this package -->
<context:component-scan base-package="levelup.world.web" />
<!-- Prepend /WEB-INF/jsp/ and append .jsp to the view name -->
<bean id="viewResolver"
class="org.springframework.web.servlet.view.InternalResourceViewResolver">
<property name="prefix" value="/WEB-INF/jsp/" />
<property name="suffix" value=".jsp" />
</bean>
<!-- Access resource bundles with the specified basename -->
<bean id="messageSource"
class="org.springframework.context.support.ReloadableResourceBundleMessageSource"
p:basename="/WEB-INF/messages/" />
</beans>
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当我运行我的应用程序时,会出现此错误
No message found under code 'country.plural' for locale 'fil_PH'
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现在在web-inf里面的我的消息文件夹里面,我有以下消息属性
messages_en.properties
messages_fr.properties
messages.properties
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我在这里失踪了什么?
"尝试为文件C:\ Users\John\documents\visual studio 2010\Projects\PAS\PAS\bin\Debug // PatAddSys.mdf附加自动命名的数据库失败.存在具有相同名称的数据库,或者无法打开指定的文件,或者它位于UNC共享上."
这有什么不对?我有正确的路径代码(我认为),但这里发生的错误仍然是我的数据库路径
private string dbPath = Application.StartupPath + "//PatAddSys.mdf";
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这是我的数据库的位置

我这里有一个清单
<ul id="demo2" data-name="demo2">
<li data-value="here">here</li>
<li data-value="are">are</li>
<li data-value="some...">some</li>
<!-- notice that this tag is setting a different value :) -->
<li data-value="initial">initial</li>
<li data-value="tags">tags</li>
</ul>
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每个li项目都有自定义数据属性.在JQuery上,如何获得具有data-value属性的每个li元素的所有值?我想得到他们的价值.
但是我的这个代码似乎没有起作用
$('#view-tags').click(function(){
$('li[data-value]').each(function(){
alert($(this).data("value"));
})
});
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关于jsfiddle的整个代码:http://jsfiddle.net/Zn3JA/
我目前正在接收一个JSON对象从我的应用程序的服务器端,结果是这样
{"tags":"[{value: 2,label: 'Dubstep'},{value: 3,label: 'BoysIIMen'},{value: 4,label:'Sylenth1'}]"}
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但是我不需要结果中的"标签"和双引号.
所以我想要的是该JSON对象的数组表示
因此,我将如何转换它
{"tags":"[{value: 2,label: 'Dubstep'},{value: 3,label: 'BoysIIMen'},{value: 4,label:'Sylenth1'}]"}
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对此
[{value: 2,label: 'Dubstep'},{value: 3,label: 'BoysIIMen'},{value: 4,label:'Sylenth1'}]
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这是创建数组的循环
String k = "[";
List<Tag> tg = audioTaggingService.findTagsByName(q);
for(int i = 0; i<audioTaggingService.findTagsByName(q).size();i++){
Tag t = tg.get(i);
if(i == (tg.size() - 1)){
k+="{value: "+t.getId()+",label:'"+t.getName()+"'}";
}else{
k+="{value: "+t.getId()+",label:'"+t.getName()+"'}";
}
}
k+="]";
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上面代码的结果就是这个
[{value: 2,label: 'Dubstep'},{value: 3,label: 'BoysIIMen'},{value: 4,label:'Sylenth1'}]
Run Code Online (Sandbox Code Playgroud) 我为Spring Security构建了自定义的Authenticaton Manager,就像这样
public class AccountAuthenticationProvider implements AuthenticationProvider{
@Autowired
private AuthenticationService authService;
@Override
public Authentication authenticate(Authentication authentication) throws AuthenticationException {
String userName = authentication.getName();
String password = (String)authentication.getCredentials();
if(authService.isValid(userName,password)){
List<GrantedAuthority> grantedAuthorityList = new ArrayList<GrantedAuthority>();
grantedAuthorityList.add(new SimpleGrantedAuthority("ROLE_USER"));
SecurityContext securityContext = new SecurityContextImpl();
return new UsernamePasswordAuthenticationToken(userName,password);
}
return null;
}
public void setAuthService(AuthenticationService authService) {
this.authService = authService;
}
@Override
public boolean supports(Class<?> authentication) {
return true;
}
}
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但是如何创建自己的自定义UserDetail对象?我将使用它来存储与帐户相关的值
我已经尝试通过curl执行此命令从我的oauth2服务器请求代码
curl -X POST -k -vu clientapp:123456 http://localhost:8080/oauth/token -H "Accept: application/json" -d "grant_type=authorization_code&scope=read%20write&client_secret=123456&client_id=clientapp&code=appcode&redirect_uri=localhost:3000"
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回应是
* Adding handle: conn: 0x608860
* Adding handle: send: 0
* Adding handle: recv: 0
* Curl_addHandleToPipeline: length: 1
* - Conn 0 (0x608860) send_pipe: 1, recv_pipe: 0
* About to connect() to localhost port 8080 (#0)
* Trying ::1...
* Connected to localhost (::1) port 8080 (#0)
* Server auth using Basic with user 'clientapp'
> POST /oauth/token HTTP/1.1
> Authorization: Basic Y2xpZW50YXBwOjEyMzQ1Ng==
> User-Agent: …Run Code Online (Sandbox Code Playgroud) 我已经仔细检查了我的URL和文件的名称,但我似乎无法显示图像.为什么会那样?这是我的代码(记下<p>身体标签内部,我没有添加完整代码,我只添加了头部和具体问题).
<html>
<head>
<title>Head First Lounge.</title>
<link type="text/css"
rel="stylesheet"
href="stylesheet/style.css"
media="screen"/>
</head>
<p class = "guarantee">
Our guarantee: at the lounge, we're committed to providing you,
our guest, with an exceptional experience every time you visit.
Whether you're just stopping by to check in on email over an
elixir, or are here for an out-of-the-ordinary dinner, you'll
find our knowledgeable service staff pay attention to every detail.
If you're not fully satisfied, have a Blueberry Bliss Elixir on …Run Code Online (Sandbox Code Playgroud) C#中的Setter和Getters如何实现封装?对于这些setter和getter,我不是新手,我有编程背景,特别是java.在java中你使用像这样的setter和getter
public class Person {
private String fName;
public void setName(String someName) {
fName = someName;
}
public String getName() {
return fName;
}
}
public class Test {
public static void main(String[] args) {
Person p = new Person();
p.setName("Bob");
System.out.println(p.getName());
}
}
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而在C#中使用速记
public class Person {
public string fName{ get; set;}
}
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C#速记getter和setter如何实现封装?我如何实现与上面的java代码相同的C#代码?对它有任何限制吗?根据我的观察,我只能使用"fName",如果它设置为public,特别是"public string fName {get; set;}",但是当涉及到private时我不能.但是当我将它设置为私有时,我无法再以其他方式访问它.
我已经完成了大量关于这个问题的谷歌搜索,到目前为止我找不到任何关于集成Struts2和Spring Security的教程.
我的问题是我如何集成Spring Security和Struts2?
我希望限制某些操作或页面,例如管理页面/网址只能由管理员和其他类似的东西访问,如果用户试图访问该页面,他或她将被重定向到另一个页面.
我正在玩DBLINK,我想尝试一下.所以我运行这个简单的查询
CREATE EXTENSION dblink;
SELECT *
FROM dblink(('dbname=genesis_admin')::text,
('SELECT * FROM user_account')::text);
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然后让我惊讶
[WARNING ] CREATE EXTENSION dblink
ERROR: extension "dblink" already exists
[WARNING ] SELECT * FROM dblink(('dbname=genesis_admin')::text, ('SELECT * FROM user_account')::text)
ERROR: function dblink(text, text) does not exist
LINE 1: SELECT * FROM dblink(('dbname=genesis_admin')::text, ('SELE...
^
HINT: No function matches the given name and argument types. You might need to add explicit type casts.
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如果它已经存在,它怎么能不存在?