我在本教程中设置了Google app engine的示例android
当我在EditText中输入内容并按下发送按钮时,暂时没有任何反应并抛出以下错误
06-10 18:47:49.109: I/CloudBackend(28741): error:
06-10 18:47:49.109: I/CloudBackend(28741): com.google.api.client.googleapis.json.GoogleJsonResponseException: 503 Service Unavailable
06-10 18:47:49.109: I/CloudBackend(28741): {
06-10 18:47:49.109: I/CloudBackend(28741): "code": 503,
06-10 18:47:49.109: I/CloudBackend(28741): "errors": [
06-10 18:47:49.109: I/CloudBackend(28741): {
06-10 18:47:49.109: I/CloudBackend(28741): "domain": "global",
06-10 18:47:49.109: I/CloudBackend(28741): "message": "",
06-10 18:47:49.109: I/CloudBackend(28741): "reason": "backendError"
06-10 18:47:49.109: I/CloudBackend(28741): }
06-10 18:47:49.109: I/CloudBackend(28741): ],
06-10 18:47:49.109: I/CloudBackend(28741): "message": ""
06-10 18:47:49.109: I/CloudBackend(28741): }
06-10 18:47:49.109: I/CloudBackend(28741): at com.google.api.client.googleapis.services.json.AbstractGoogleJsonClientRequest.newExceptionOnError(AbstractGoogleJsonClientRequest.java:111)
06-10 18:47:49.109: I/CloudBackend(28741): at com.google.api.client.googleapis.services.json.AbstractGoogleJsonClientRequest.newExceptionOnError(AbstractGoogleJsonClientRequest.java:38)
06-10 18:47:49.109: I/CloudBackend(28741): …
Run Code Online (Sandbox Code Playgroud) 嗨我有一个"/",编码后,%2F.问题是,当我将其添加为URL的一部分并打开时,抛出404,因为存在/之间.所以我的问题是在PHP中有什么方法我们可以1.加密并获得一个永远不会给出任何特殊字符的字符串2.将盐传递给加密.
顺便说一下我的加密方法:
$string='16';
$key='ec5dc8c8'
$cipher_alg = MCRYPT_TRIPLEDES;
$iv = mcrypt_create_iv(mcrypt_get_iv_size($cipher_alg,MCRYPT_MODE_ECB), MCRYPT_RAND);
$encrypted_string = mcrypt_encrypt($cipher_alg, $key, $string, MCRYPT_MODE_ECB, $iv);
return base64_encode($encrypted_string);
Run Code Online (Sandbox Code Playgroud)
注意:当我使用这个特殊的字符串和键集时,我可以生成一个字符串来解决这个问题.