是否有可能只在CSS 2.1中实现水平溢出?
overflow: auto;
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将导致块元素同时具有水平和垂直滚动条.我想要一个块元素(比方说<div>),它只显示水平滚动条.我怎么做?
可能吗?这是我的输入字符串:
? š ? ? ž ý á í é ? Á Ž Ý
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这是我想要的输出:
l s c t z y a i e C A Z Y
Run Code Online (Sandbox Code Playgroud) 将此添加到CSS不起作用:
.ui-dialog-buttonpane { text-align: center; }
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按钮仍然在右侧.
我该怎么办?
我发现这个函数使用libjpeg写入文件:
int write_jpeg_file( char *filename )
{
struct jpeg_compress_struct cinfo;
struct jpeg_error_mgr jerr;
/* this is a pointer to one row of image data */
JSAMPROW row_pointer[1];
FILE *outfile = fopen( filename, "wb" );
if ( !outfile )
{
printf("Error opening output jpeg file %s\n!", filename );
return -1;
}
cinfo.err = jpeg_std_error( &jerr );
jpeg_create_compress(&cinfo);
jpeg_stdio_dest(&cinfo, outfile);
/* Setting the parameters of the output file here */
cinfo.image_width = width;
cinfo.image_height = height;
cinfo.input_components = bytes_per_pixel;
cinfo.in_color_space = color_space; …Run Code Online (Sandbox Code Playgroud) 我在我的FreeBSD 8.2盒子上安装了Emacs.一切正常,但我不能使用标签.当我使用emacs和命中标签编辑文件时,没有任何反应.
可能是什么导致了这个?
民意调查的最佳数据库架构是什么?一对多的关系对此有利吗?我正在考虑有两张桌子:
poll_questions
int id
varchar body
datetime created_at
datetime updated_at
poll_answers
int id
varchar body
int votes default 0
int question_id (foreign key to poll_questions.id)
datetime created_at
datetime updated_at
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然后还会有第三个表来跟踪谁投票给答案,这样用户只能投票一次:
poll_voting_history
int id
int question_id (foreign key to poll_questions.id)
int answer_id (foreign key to poll_answers.id)
int user_id (foreign key to the id in the users table)
datetime created_at
datetime updated_at
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你的想法是什么?我在想它吗?
我不明白.XSLX表大约3MB,甚至1024MB的RAM还不足以让PHPExcel将其加载到内存中?
我可能在这里做了一些可怕的错误:
function ReadXlsxTableIntoArray($theFilePath)
{
require_once('PHPExcel/Classes/PHPExcel.php');
$inputFileType = 'Excel2007';
$objReader = PHPExcel_IOFactory::createReader($inputFileType);
$objReader->setReadDataOnly(true);
$objPHPExcel = $objReader->load($theFilePath);
$rowIterator = $objPHPExcel->getActiveSheet()->getRowIterator();
$arrayData = $arrayOriginalColumnNames = $arrayColumnNames = array();
foreach($rowIterator as $row){
$cellIterator = $row->getCellIterator();
$cellIterator->setIterateOnlyExistingCells(false); // Loop all cells, even if it is not set
if(1 == $row->getRowIndex ()) {
foreach ($cellIterator as $cell) {
$value = $cell->getCalculatedValue();
$arrayOriginalColumnNames[] = $value;
// let's remove the diacritique
$value = iconv('UTF-8', 'ISO-8859-1//TRANSLIT', $value);
// and white spaces
$valueExploded = explode(' ', $value);
$value = …Run Code Online (Sandbox Code Playgroud) 所以我创建一个新的图像元素,一旦我从AJAX调用响应像这样的图像元数据:
var loadedImageContainter = $('<div class="loaded-image-container"></div>');
var image = $('<img src="' + file.url + '" alt="">');
loadedImageContainter.append(image);
$('.loading-image').replaceWith(loadedImageContainter);
var width = image.width();
var height = image.height();
console.log(width);
console.log(height);
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但是width()和height()函数返回0,尽管图像大小为30 x 30 px并且它在页面上正确显示.我需要获得它的尺寸才能绝对定位图像.
这是我的代码,我试图在一种文档类型上发送正确的标题.我找到了pdf,doc和docx的标题,但我仍然需要知道Excel和Powerpoint文件的正确标题.
任何帮助赞赏.
$document = urldecode($_GET['document']);
$extension = end(explode('.', $document));
$mimeType = '';
switch ($extension) {
case 'pdf':
$mimeType = 'pdf';
break;
case 'doc':
$mimeType = 'msword';
break;
case 'docx':
$mimeType = 'msword';
break;
case 'xls':
$mimeType = '';
break;
case 'xlsx':
$mimeType = '';
break;
case 'ppt':
$mimeType = '';
break;
case 'pptx':
$mimeType = '';
break;
}
header('Content-type: application/' . $mimeType);
Run Code Online (Sandbox Code Playgroud) 我有一个带有HTML标记的DOM对象.我正在尝试替换所有嵌入式标签,如下所示:
<embed allowfullscreen="true" height="200" src="path/to/video/1.flv" width="320"></embed>
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使用这样的标签:
<a
href="path/to/video/1.flv"
style="display:block;width:320px;height:200px;"
id="player">
</a>
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我很难解决这个问题,我不想为此使用正则表达式.你能救我吗?
编辑:
这是我到目前为止:
// DOM initialized above, not important
foreach ($dom->getElementsByTagName('embed') as $e) {
$path = $e->getAttribute('src');
$width = $e->getAttribute('width') . 'px';
$height = $e->getAttribute('height') . 'px';
$a = $dom->createElement('a', '');
$a->setAttribute('href', $path);
$a->setAttribute('style', "display:block;width:$width;height:$height;");
$a->setAttribute('id', 'player');
$dom->replaceChild($e, $a); // this line doesn't work
}
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