小编Zoe*_*kov的帖子

我有一个char数组,其中包含用户输入的内容.我怎么算数字呢？允许用户做一些疯狂的事情:

hello this
               is a test
   how are
you today?

所以这里的单词数量应为9,但我的程序告诉我23.为什么这不起作用？它计算空间,但我考虑到了这一点sentence_entered[i + 1] != ' '

我的代码:

int i = 0;    
while (sentence_entered[i] != '\0') {

        if (
            (sentence_entered[i] == ' ' ||
            sentence_entered[i] == '\n') &&
            (sentence_entered[i + 1] != ' ' ||
            sentence_entered[i + 1] != '\n')
           ) {
            words += 1;
    }
i++
}

如何检查是否char *name为空？

#include <stdio.h>
#include <string.h>

void store_stuff(char **name, int *age);
int main(void) {

    char *name;
    int age;

    store_stuff(&name, &age);

    printf("Name: %s\n", name);
    printf("Age: %d\n", age);

}

void store_stuff(char **name, int *age) {

    *age = 31;

    if (name == NULL) { // how can I check here if char name is empty?
        *name = "ERROR";
    }

}