小编app*_*wil的帖子

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您无法重新设置加密变量的密钥

例如，如果这是 的内容group_vars/all.yaml，我想重新加密所有加密的变量。

key_tab: !vault |
  $ANSIBLE_VAULT;1.1;AES256
  30333939663734636530386263663437343431353539643366633534366239643763326138653232
  3562383132623937346138613833396563653038646165300a623061363063663132373739373031
  66623133393239376366383235353332366336386532643637343438653634633734346639636334
  3633363032376339340a663531346633623466643163353638303534313937663931633962383637
  3637
certs:
  - file: client.cert
    password: !vault |
      $ANSIBLE_VAULT;1.1;AES256
      35626163653930386265393064326330393433343763626534373330393432373231633365656534
      6237626631326634333963313733356531623239653161370a356666326631663565396633396139
      32303962343064343530383364616235343130373935313161353135613539653061363735336337
      3636633036313565640a663736613065396262336433653564373161393431636661666134643761
      3639

我尝试用一​​些 bash 命令来做到这一点，但由于缩进，它变得很复杂。

是否有一种自动化的方法来完成此重新密钥？

为什么某些 IPv6 地址在使用时会转换为 IPv4 地址InetAddress.getByName？

例如，我希望这两个地址::f:f:f，::ffff:f:f转换为Inet6Address

然而，这个::ffff:f:f变成Inet4Address

import java.net.InetAddress;
class Main {
  public static void main(String[] args) throws Exception {
    // Interpreted as IPv6
    var address = InetAddress.getByName("::f:f:f");
    System.out.println(address); // /0:0:0:0:0:f:f:f
    System.out.println(address.getClass()); // class java.net.Inet6Address
    
    // Interpreted as IPv4
    address = InetAddress.getByName("::ffff:f:f");
    System.out.println(address); // /103.30.217.152
    System.out.println(address.getClass()); // class java.net.Inet4Address
  }
}