小编Kai*_*r69的帖子

我无法将这段代码从 Javascript 转换为 Typescript。

问题是转换 ...spread 运算符。

function calculateCombinations(first, next, ...rest) {

  if (rest.length) {
    next = calculateCombinations(next, ...rest);
  }


  return first.flatMap(a => next.map(b => [a, b].flat()));
}


a1 = ['A', 'B']
a2 = ['+', '-']
a3 = ['1', '2']
a4 = ['X', 'Y', 'Z']
// Show possibile combinations
calculateCombinations(a1, a2, a3, a4); // give me an array of 24 combinations

尝试转换为 TS：

  function calculateCombinationsTS(first: any[], next: any[], ...rest: any[]) {
    if (rest.length) {
        next = calculateCombinationsTS(next, ...rest);
    }

   return …

我有这个代码:

Sidebar.jsx

class Sidebar extends Component {
    render() {
    return (
        <div className="sidebar">
          { this.props.children }
        </div>
    );
  }
}


class Item extends Component {
  render() {
    return (
        <div>
            <b> { this.props.name } </b>
        </div>
    );
  }
}

export { Sidebar, Item };

index.js

export {default as Header} from './Header';
export {default as Footer} from './Footer';
export {default as Sidebar, Item} from './Sidebar';

app.jsx

import { Sidebar } from '../components';
class App extends Component {
  render() {

    return ( …

我对GSON-JSON有点问题.

让我们看看以下代码:

    public static class ProtoQuery {
    public String action;
    public String token;
    public Object params;

    public ProtoQuery(String action, String token, Object params) {
        this.action = action;
        this.token = token;
        this.params = params;
    }
}


// Authentication Phase
public static class ProtoAuth {
    public String username;
    public String password;

    public ProtoAuth(String username, String password) {
        this.username = username;
        this.password = password;
    }
}


    // Serialize Object
    Gson gson = new Gson();
    ProtoQuery tmp = new ProtoQuery("ProtoAuth", "", new JirckeProtocol.ProtoAuth("ABC", "myPASS")); …

只是尝试学习Invoke/BeginInvoke,我遇到了那个问题.

       // Update UI
       public void UpdateForm(string value) {
        txtLog.AppendText(value + "\r\n");
       }


       // Thread function
       private void readSocket() {
        string row = "";

        while (socket.Connected) {                
            row = socket.readLine();            

            if (IsControlValid(this))
                BeginInvoke((MethodInvoker)delegate { UpdateForm(String.Copy(row)); });                    

        }
    }

使用Invoke方法我的UI更新与正确的文本,而不是如果我使用BegineInvoke我看到错误的文本,即一些文本反复很多时间.我知道那个电话

BeginInvoke((MethodInvoker)delegate { UpdateForm(row); });  

也许"行"可以像共享变量一样行为而不是

BeginInvoke((MethodInvoker)delegate { UpdateForm(String.Copy(row)); });                    

我认为每个BeginInvoke调用都会创建一个"新"委托,因此使用String.Copy必须创建另一个字符串实例,但我看到总是错误的值(重复,ecc).

哪里我错了？