小编use*_*369的帖子

我想知道是否有人知道如何用ac#命令打开这个盒子？

提前致谢!

我在用Autofac注册IRequest和IRequestHandler接口时遇到麻烦。此代码有效：

var builder = new ContainerBuilder();
builder.RegisterAssemblyTypes(typeof(IMediator).GetTypeInfo().Assembly).AsImplementedInterfaces();
builder.RegisterAssemblyTypes(typeof(Ping).GetTypeInfo().Assembly).AsImplementedInterfaces();
builder.RegisterControllers(Assembly.GetExecutingAssembly());
builder.RegisterApiControllers(Assembly.GetExecutingAssembly());

现在，我想使其更加灵活，以避免必须注册使用接口的所有类。

我没有运气尝试过这个：

builder.RegisterGeneric(typeof(IRequest<>)).AsImplementedInterfaces();
builder.RegisterGeneric(typeof(IRequestHandler<,>)).AsImplementedInterfaces();

这是我的Ping班：

public class Ping : IRequest<Pong>
{
    public string Message { get; set; }
}

public class Pong
{
    public string Message { get; set; }
}

public class PingHandler : IRequestHandler<Ping, Pong>
{
    public Pong Handle(Ping message)
    {
        return new Pong { Message = message.Message + " Pong" };
    }
}

有任何想法吗？

我试图将一个数组分配给我的letter.charData,但我收到此错误:

IntelliSense:表达式必须是可修改的左值

我试图将我的数组arr添加到letter.charData

提前致谢!

struct _Letter{
    char character;
    int width;
    int charData[8][5];
};

typedef struct _Letter Letter;

Letter *allocLetter(void)
{
    Letter *letter;

    letter = (Letter*) malloc(1 * sizeof(Letter));

    letter->character = NULL;
    letter->width = NULL;

    /* charData? */

    return letter;
}

int main(void)
{ 
    Letter letter = *allocLetter();

    int arr[8][5] = 
    {
        0,0,0,0,0,
        1,0,0,0,0,
        1,0,0,0,0,
        1,0,0,0,0,
        1,0,0,0,0,
        1,0,0,0,0,
        1,0,0,0,0,
        1,0,0,0,0
    };

    letter.character = '1';
    letter.charData = arr;

    return(0);
}