为什么我无法控制输出$ scope值？我正在尝试从页面中提取用户指定的值并在控制器中检索.最终我想将此传递给服务,以便多个控制器可以访问这些数据.
HTML
<!DOCTYPE html>
<html lang="en-us" ng-app="myApp">
<head>
<meta http-equiv="X-UA-Compatible" content="IE=Edge">
<meta charset="UTF-8">
<link rel="stylesheet" href="css/bootstrap.min.css" />
<!-- CDN lib files -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" />
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.4.8/angular.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular.js/1.4.8/angular-animate.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/angular-ui-bootstrap/1.1.0/ui-bootstrap-tpls.min.js"></script>
<!-- custom angular script -->
<script src="js/app.js"></script>
</head>
<body>
<div class="container">
<div ng-controller="mainController">
<h1>Hello world!</h1>
<label> Please enter something</label>
<input textarea ng-model="name"></input>
<h4> This is what you entered : {{ name }} </h4>
<h4 style=color:red> now filtering: {{ lower() }}</h4>
</div>
</div>
</body>
</html>
APP.JS
var myApp …javascript angularjs angularjs-scope console.log angularjs-controller
我有一个解决方案来检查从对象中提取的NULL值,但我觉得可能有比我在这里做的更好的方法.所以请建议我使用代码片段的最佳方法 :)
我将把我的xml内容传递给unmarshalling方法然后将unmarshalledValues传递给null检查方法(即ValidateInputFiled)
Contents unmarshalledValues = unmarshalingContent( xml );
inputCheck = ValidateInputField( unmarshalledValues );
我有一个POJO用于我的XML元素,如下所述,
@XmlRootElement( name = "contents" )
public class Contents
{
@XmlElement
String A;
@XmlElement
String B;
@XmlElement
String C;
@XmlAttribute
String D;
public String getA()
{
return A;
}
public String getB()
{
return B;
}
public String getC()
{
return C;
}
public String getD()
{
return D;
}
}
我已经定义了ValidateInputFiled,如下所述
public Boolean ValidateInputField( Contents unmarshalledValues )
{
int checker …我想使用 JavaScript 或 Angularjs 或任何 javascript 库将此示例数据集复制到嵌套的 JSON 中。
数据：
PrimaryId,FirstName,LastName,City,CarName,DogName
100,John,Smith,NewYork,Toyota,Spike
100,John,Smith,NewYork,BMW,Spike
100,John,Smith,NewYork,Toyota,Rusty
100,John,Smith,NewYork,BMW,Rusty
101,Ben,Swan,Sydney,Volkswagen,Buddy
101,Ben,Swan,Sydney,Ford,Buddy
101,Ben,Swan,Sydney,Audi,Buddy
101,Ben,Swan,Sydney,Volkswagen,Max
101,Ben,Swan,Sydney,Ford,Max
101,Ben,Swan,Sydney,Audi,Max
102,Julia,Brown,London,Mini,Lucy
Javascript：
var file = reader.result;
var singleRow = readerFile.split(/\r\n|\n/);
var header = singleRow[0].split(',');
var result =[];
for ( var i=1; i < file.length; i++ ){
var elementData = singleRow[i].split(',');
elementData = elementData.filter(function(n){ return n != "" });
var Obj = {};
for ( var j=0; j < header.length; j++ ){
Obj[header[j]] = elementData[j];
/*
- How can i …MySQL使用"IS NULL"而不是"NULL",那么如何绑定变量来实现相同的呢？
现在我尝试了这个
selectStmt.setNull( 2, java.sql.Types.VARCHAR );
当我打印"java.sql.Types.VARCHAR"显示值= 12？如果是这样,在准备好的情况下如何设置"IS NULL"？
更多细节:
即如果我在输入中有string ="",我感兴趣的是查询(MySQL)为null.所以逻辑是这样的,
Connection c = SQLCon.connect();
PreparedStatement selectStmt = c.prepareStatement( "select * from "
+ TableName
+ " where P = ? AND M = ? AND PR = ? AND DR = ? " );
if ( P.trim().equals( "" ) )
{
selectStmt.setNull( 1, java.sql.Types.VARCHAR );
} else
{
selectStmt.setString( 1, P );
}
if ( M.trim().equals( "" ) )
{
selectStmt.setNull( 2, java.sql.Types.VARCHAR );
} else
{ …form.html
<md-button class="md-raised md-primary pull-right formPage" ng-disabled="formPage.$invalid" ng-click ="submit()">SAVE</md-button>
的CSS
.md-button.md-raised.md-primary.formPage {
position: right !important;
color: #FFFFFF;
background-color:#008cba;
}
按钮已禁用，但具有来自CSS的自定义颜色。如何显示默认的禁用样式，或者如果禁用则更改按钮颜色？
angularjs ×2
java ×2
javascript ×2
arrays ×1
button ×1
console.log ×1
css ×1
data-binding ×1
json ×1
list ×1
mysql ×1
null ×1