小编Pan*_*kaj的帖子

我有以下XML.

<?xml version="1.0" encoding="UTF-8"?>
<Employees>
    <Employee id="3">
        <age>40</age>
        <name>Tom</name>
        <gender>Male</gender>
        <role>Manager</role>
    </Employee>
    <Employee id="4">
        <age>25</age>
        <name>Meghna</name>
        <gender>Female</gender>
        <role>Manager</role>
    </Employee>
</Employees>

我想选择id ="4"的Employee元素.

我正在使用XPath表达式下面没有返回任何东西.

//Employee/[@id='4']/text()

我在http://chris.photobooks.com/xml/default.htm检查了它,它说无效的xpath,不知道问题出在哪里.

我正在使用Hibernate最新版本4.3.5.Final.

我的hibernate.cfg.xml文件内容:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC
    "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
    "http://hibernate.org/dtd/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
    <property name="hibernate.connection.driver_class">com.mysql.jdbc.Driver</property>
    <property name="hibernate.connection.url">jdbc:mysql://localhost/Test</property>
    <property name="hibernate.connection.username">pankaj</property>
    <property name="hibernate.connection.password">xxxx</property>
    <property name="hibernate.dialect">org.hibernate.dialect.MySQLDialect</property>

    <mapping resource="employee.hbm.xml"/>
</session-factory>

</hibernate-configuration>

用于创建SessionFactory的实用程序类:

package com.example;
import org.hibernate.SessionFactory;
import org.hibernate.boot.registry.StandardServiceRegistryBuilder;
import org.hibernate.cfg.Configuration;

public class HibernateUtil {

private static final SessionFactory sessionFactory = buildSessionFactory();

private static SessionFactory buildSessionFactory() {
    try {
        // Create the SessionFactory from hibernate.cfg.xml
        Configuration configuration = new Configuration();
        configuration.configure("hibernate.cfg.xml");
        System.out.println("Hibernate Configuration loaded");

        SessionFactory sessionFactory = configuration.buildSessionFactory(new StandardServiceRegistryBuilder().build()); …

我是Scala编程的新手,有人可以在下面给我解释警告原因吗？

我试图找到原因,它似乎是一个很大的修复:https://issues.scala-lang.org/browse/SI-6439

那么为什么我会收到这个警告？

我的示例Web服务正在返回XML.

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<errorResponse>
<errorCode>Wrong ID</errorCode>
<errorId>2</errorId>
</errorResponse>

以下测试通过.

response.then().body("errorResponse.errorId", Matchers.is("2"));
response.then().body("errorResponse.errorCode", Matchers.is("Wrong ID"));

response.then().body("errorResponse1.errorCode", Matchers.is("Wrong ID"));
response.then().body("errorResponse2.errorCode", Matchers.is("Wrong ID"));

我知道前两个测试都很好,我没有得到的是为什么最后两个测试通过了？

我正在尝试创建一个简单的 Spring Boot Session 项目。这是 Spring Initializr 的基本设置。我收到以下错误：

2018-06-20 12:59:24.318  INFO 8108 --- [           main] c.j.s.SpringSessionExampleApplication    : Starting SpringSessionExampleApplication on pankaj with PID 8108 (/Users/pankaj/Documents/workspace-sts-3.9.4.RELEASE/Spring-Session-Example/target/classes started by pankaj in /Users/pankaj/Documents/workspace-sts-3.9.4.RELEASE/Spring-Session-Example)
2018-06-20 12:59:24.329  INFO 8108 --- [           main] c.j.s.SpringSessionExampleApplication    : No active profile set, falling back to default profiles: default
2018-06-20 12:59:24.372  INFO 8108 --- [           main] ConfigServletWebServerApplicationContext : Refreshing org.springframework.boot.web.servlet.context.AnnotationConfigServletWebServerApplicationContext@39de3d36: startup date [Wed Jun 20 12:59:24 IST 2018]; root of context hierarchy
WARNING: An illegal reflective access operation has occurred …

x=5
print(eval('x+1',{'__builtins__': None}))

得到错误:

TypeError: 'NoneType' object is not subscriptable

为什么我会出错？

另外,如何只为eval()函数指定一些内置方法？例如,仅允许max和min功能.

我对下面的代码感到困惑,Eclipse将编译器错误显示为"此静态方法无法从Super中隐藏实例方法",但在执行时它工作正常.

package com.journaldev.java;

public class Test {

    public static void main(String[] args) {
        Super s = new Subclass();
        s.foo();
    }
}

class Super {
    void foo() {
        System.out.println("Super");
    }
}

class Subclass extends Super {
    static void foo() {
        System.out.println("Subclass");
    }

}

看下图中的输出,有人可以澄清一下吗？