小编TTY*_*358的帖子

假设我想创建一个zip函数：

function zip(arrays){
    // assume more than 1 array is given and all arrays 
    // share the same length
    const len = arrays[0].length;
    const toReturn = new Array(len);
    for (let i = 0; i < len; i++){
        toReturn[i] = arrays.map(array=>array[i]);
    }
    return toReturn;
}

console.log(zip([
    [1,2,3],
    [4,5,6],
    [7,8,9],
    [10,11,12],
]));
/*
Output:
(3) [Array(4), Array(4), Array(4)]
0: (4) [1, 4, 7, 10]
1: (4) [2, 5, 8, 11]
2: (4) [3, 6, 9, 12]
*/

为了在所有数组都包含相同类型的元素时定义此函数：

    function zip<T>(arrays: …