我正在尝试从另一个查询执行查询,但Django说:'渲染时捕获了DatabaseError:子查询返回的行数超过1行.我正在使用PostGis.
我的模特
class Place(models.Model):
coordinate = models.PointField()
class TranslatedPlace(models.Model):
place = models.ForeignKey(Place)
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我的看法
near_coordinates = Place.objects.filter(coordinate__distance_lte=(place_obj.coordinate, D(km=100)))
near_places = TranslatedPlace.objects.filter(place=near_coordinates)
Run Code Online (Sandbox Code Playgroud) 我收到此错误:渲染时捕获AttributeError:'dict'对象没有属性'友谊'.问题是当我尝试在自定义模板标记中获取friend.friend的值时.模块'friends_for_user'是对的.我有:
楷模
class FriendshipManager(models.Manager):
def friends_for_user(self, user):
friends = []
for friendship in self.filter(from_user=user).select_related(depth=1):
friends.append({"friend": friendship.to_user, "friendship": friendship})
for friendship in self.filter(to_user=user).select_related(depth=1):
friends.append({"friend": friendship.from_user, "friendship": friendship})
return friends
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模板标签
def render(self, context):
user = self.user.resolve(context)
num = self.num.resolve(context)
my_friends = Friendship.objects.friends_for_user(user)
potential_friends = []
for friend in my_friends:
potential_friends.append(Friendship.objects.friends_for_user(friend.friend)) //This line is the error.
context[self.context_name] = potential_friends
return ''
Run Code Online (Sandbox Code Playgroud) 我正在尝试将django-voting应用程序添加到我的项目中.我不知道如何在我的模板中使用它,所以当用户点击按钮时,我会添加一个新的模板标签用于向上或向下投票.我不知道是否有良好的形式来做到这一点.
我的问题是模板标签中的这些行:
obj = Place.objects.filter(id=object_id)
Vote.objects.record_vote(obj, self.user, +1)
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django打印:
Caught AttributeError while rendering: 'Place' object has no attribute '_meta'
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如何添加属性_meta我的对象'Place'?
我正在尝试使用Google示例页面从网址下载图片.我在BitmapFactory.decodeStream方法中使用InputStream时读过,我不能使用两次.我试图这样做,但它不起作用'因为它在解码图像中返回null,我不知道我能做什么.
这是我的代码:
这部分是在AsyncTask类中的doInBackground方法中
Bitmap bitmapImage;
URL imageUrl = null;
try {
imageUrl = new URL(url[0]);
HttpGet httpRequest = null;
httpRequest = new HttpGet(imageUrl.toURI());
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response = (HttpResponse) httpclient.execute(httpRequest);
HttpEntity entity = response.getEntity();
BufferedHttpEntity bufHttpEntity = new BufferedHttpEntity(entity);
InputStream instream = bufHttpEntity.getContent();
bitmapImage = CommonMethods.decodeSampledBitmapFromResource(instream, thumb_width, thumb_width);
instream.close();
return bitmapImage;
} catch (URISyntaxException e) {
e.printStackTrace();
return null;
} catch (MalformedURLException e) {
e.printStackTrace();
return null;
} catch (IOException e) {
e.printStackTrace(); …Run Code Online (Sandbox Code Playgroud)