我正在尝试从地图中获取一个列表，并基于 id 的列表，并希望根据年龄（年龄 > 35）检索值（列表）
def people = [
"1": [[name:'Bob', age: 32, gender: 'M'],[name:'Johnny', age: 36, gender: 'M']],
"3": [[name:'Claire', age: 21, gender: 'F'],[name:'Amy', age: 54, gender:'F']],
"4": [[name:'John', age: 41, gender: 'F'],[name:'Sam', age: 54, gender:'F']]
]
def id = ["1","3"]
def age = people.subMap(id).values().findAll{it.age > 35}
但是，我收到以下错误：
Cannot compare java.util.ArrayList with value '[32, 36]' and java.lang.Integer with value '35'
如何获取所有年龄 > 35 岁的人员的名单？