小编Kri*_*hna的帖子

有没有办法通过排除某些类来有目的地增加 SonarQube 中的代码覆盖率值。

我用{ provide: LocationStrategy, useClass: HashLocationStrategy },我的app.module.ts。但是，当我给this.route.url它总是包含/不管我在/home或/dashboard或/profile

我需要获取特定的路线值

constructor(public router:Router) {} alert(this.router.url);

我想results根据存储在过滤器中的值过滤我的数组。我试过下面的代码。但它不适用。

let filters = {
  name: ["Krishna", "Naveen"],
  city : ["London"]
};
results = [
{
    "name": "Krishna#Surname",
    "city": "London",
    "age": 23
},
{
    "name": "Naveen#Surname",
    "city": "London",
    "age": 23
},
{
    "name": "Krishna#Surname",
    "city": "NewYork",
    "age": 23
},
{
    "name": "Praveen#Surname",
    "city": "Washington",
    "age": 23
}
]
this.results1 = this.multiFilter(results,filters);

multiFilter(array:any=[], filters:Object) {
const filterKeys = Object.keys(filters);
return array.filter((item) => {
  return filterKeys.every(key => {
    let filters1= filters[key];
    return filters1.every(key1 => {
      return !!~ item[key].indexOf(key1)
    });
  }); …

我正在尝试使用pyspark连接到MongoDB.下面是我正在使用的代码

from pyspark import SparkConf, SparkContext
from pyspark.sql import SQLContext

sparkConf = SparkConf().setAppName("App")
sparkConf.set("spark.mongodb.input.uri", "mongodb://127.0.0.1/mydb.test")
sc = SparkContext(conf = sparkConf)
sqlContext =SQLContext(sc)
df = sqlContext.read.format("com.mongodb.spark.sql.DefaultSource").load()
df.printSchema()

我面临以下错误

py4j.protocol.Py4JJavaError: An error occurred while calling o25.load.
java.lang.ClassNotFoundException: Failed to find data source: com.mongodb.spark.sql.DefaultSource.

我的数据框看起来像

+-------------------------+-----+
| Title| Status|Suite|ID  |Time |
+------+-------+-----+----+-----+
|KIM   | Passed|ABC  |123 |20   |
|KJT   | Passed|ABC  |123 |10   |
|ZXD   | Passed|CDF  |123 |15   |
|XCV   | Passed|GHY  |113 |36   |
|KJM   | Passed|RTH  |456 |45   |
|KIM   | Passed|ABC  |115 |47   |
|JY    | Passed|JHJK |8963|74   |
|KJH   | Passed|SNMP |256 |47   |
|KJH   | Passed|ABC  |123 |78   |
|LOK   | Passed|GHY  |456 |96   |
|LIM   | Passed|RTH  |113 |78   |
|MKN   | Passed|ABC  |115 |74   |
|KJM …

下面的代码在Mozilla和Chrome中运行正常。但是在Safari中无法播放视频。

<video id="v-control" width="100%" autoplay="autoplay" loop>
    <source src="assets/img/web home page banner.mp4" type="video/mp4" 
    media="all and (max-width: 480px)">
    <source src="video-small.webm" type="video/webm" media="all and 
    (max-width: 480px)">
    <source src="assets/img/web home page banner.mp4" type="video/mp4">
    <source src="video.webm" type="video/webm">
</video>

我已经尝试preload过使用视频标签，如果要添加controls，则应单击“播放”按钮。我不需要视频的任何控件，因此我删除了控件。

我创建了一个Vue项目，其中Typescript包含类风格的组件。我需要包含一些外部 CSS 文件 - 例如来自Amazon S3. CSS 似乎没有加载。

在网络部分我可以看到它。

我编写了一些代码，它将根据浏览器本地存储中存储的标志向我显示一个确认对话框。

if(localStorage.getItem('visitedPage') == 'true') {
  this.alertService.confirmThis("Are you sure?",function(){
    console.log("Yes");
  },function(){
    console.log("No");
  })
} else {
  localStorage.setItem('visitedPage','true');
}

But I can see that dialog only after the page refresh (the entire content goes off, the page loads & the dialog opens). But I need that dialog immediately on hitting refresh.

Any suggestions or examples please!!