小编jur*_*rij的帖子

我有十六进制值存储为字符:

char A = '0';
char B = '6';
char C = 'E';

......我需要它们转换为整数.我知道'atoi',但这仅适用于十进制编码的char值.任何类似的功能？

如何初始化特殊的ASCII字符,例如EOT(0x04),ENQ(0x05)？

char CHAR1 = '\EOT';
char CHAR2 = '\ENQ';

它是否正确？

我正在使用STM32F4Discovery工具包来构建一个简单的CAN接口.我设法配置它,所以我可以传输CAN消息,但是,我坚持接收它们.据我所知,要接收CAN消息,它必须通过验收过滤器.我想设置过滤器接受从ID 0x700到0x7FF的所有(标准,2.0A)消息.我该怎么做呢？

我已阅读参考手册,但我不知道如何实际配置过滤.

void CAN_FilterConfiguration(void) {
    CAN_FilterInitTypeDef CAN_FilterInitStructure;

    /* CAN2 filter configuration */
    CAN_FilterInitStructure.CAN_FilterNumber = 1; // filter number = 1 (0<=x<=13)
    CAN_FilterInitStructure.CAN_FilterMode = CAN_FilterMode_IdMask;
    CAN_FilterInitStructure.CAN_FilterScale = CAN_FilterScale_16bit;
    CAN_FilterInitStructure.CAN_FilterIdHigh = 0x0000;
    CAN_FilterInitStructure.CAN_FilterIdLow = 0x0000;
    CAN_FilterInitStructure.CAN_FilterMaskIdHigh = 0x0000;
    CAN_FilterInitStructure.CAN_FilterMaskIdLow = 0x0000;
    CAN_FilterInitStructure.CAN_FilterFIFOAssignment = CAN_FIFO0; // FIFO = 0
    CAN_FilterInitStructure.CAN_FilterActivation = ENABLE;
    CAN_FilterInit(&CAN_FilterInitStructure);
}

如何在C中初始化新的行char？

例如,要初始化char A:

char letter = 'A';

如何初始化新行？也许这样:

char newLine = '0x0A'?