小编tra*_*cer的帖子

我有下面的对象数组,id为唯一键":

var test = [
  {id: 1, PlaceRef: "*00011", Component: "BATH", SubLocCode: "BAT", BarCode: ""},
  {id: 2, PlaceRef: "*00022", Component: "BAXI10R", SubLocCode: "KIT", BarCode:""},
  {id: 1, PlaceRef: "*00011", Component: "BATH", SubLocCode: "BAT", BarCode: ""},
  {id: 3, PlaceRef: "*00011", Component: "ANR190", SubLocCode: "B1", BarCode: ""}
]

从这里我想使用spread运算符检索唯一对象,我尝试使用下面的代码:

const uniKeys = [...(new Set(test.map(({ id }) => id)))];

我只能检索id,如何使用spread运算符检索唯一对象.此外,任何新的ES6功能实现都会有所帮助.

我有两个对象数组说，

var deSelectedRows = [
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, id: "BRIC01"},
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, id: "BRIC02"},
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, id: "BRIC03"},
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, id: "BRIC04"}
];

var selectedRows = [
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, id: "BRIC01"},
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, id: "BRIC02"},
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, id: "BRIC03"},
{ PoHeaderKey: 129, OrderNo: "WS1", LineNo: 1, …

我有两个字符串如下：

var str1 = "5YRS,AC,ALAR";
var str2 = "MON,5YRS,TRAU";

我想将这两个字符串合并为一个字符串并删除其中的重复项。我尝试了以下方法：

var main_str = str1.concat(str2) //result: "5YRS,AC,ALARMON,5YRS,TRAU"

我得到的结果最终被合并，如果我动态推送任何字符串，它不会显示所需的结果。是否有任何新的 ES6 实现来获取检查 null 检查并返回唯一字符串值的方法。