我成功地使用smtplib模块发送电子邮件.但是,当发送emial时,它不包括发送的电子邮件中的主题.
import smtplib
SERVER = <localhost>
FROM = <from-address>
TO = [<to-addres>]
SUBJECT = "Hello!"
message = "Test"
TEXT = "This message was sent with Python's smtplib."
server = smtplib.SMTP(SERVER)
server.sendmail(FROM, TO, message)
server.quit()
如何编写"server.sendmail"以在发送的电子邮件中包含SUBJECT.
如果我使用server.sendmail(FROM,TO,message,SUBJECT),则会出现关于"smtplib.SMTPSenderRefused"的错误
在Python中,如果我使用"wget"使用os.system("wget")下载文件,它会在屏幕上显示如下:
Resolving...
Connecting to ...
HTTP request sent, awaiting response...
100%[====================================================================================================================================================================>] 19,535,176 8.10M/s in 2.3s
等等在屏幕上.
如何将此输出保存在某个文件中而不是在屏幕上显示？
目前我运行的命令如下:
theurl = "< file location >"
downloadCmd = "wget "+theurl
os.system(downloadCmd)
我知道如何列出目录树中的所有子目录和文件.但我正在寻找方法列出所有新创建的文件,修改和(如果可能)从根目录开始在目录树中的所有目录中删除的文件.
我想打开一个进程并在同一进程中运行两个命令.我有 :
cmd1 = 'source /usr/local/../..'
cmd2 = 'ls -l'
final = Popen(cmd2, shell=True, stdin=PIPE, stdout=PIPE, stderr=STDOUT, close_fds=True)
stdout, nothing = final.communicate()
log = open('log', 'w')
log.write(stdout)
log.close()
如果我使用popen两次,这两个命令将在不同的进程中执行.但我希望它们在同一个shell中运行.
尝试在我的系统(MAC OS X)中安装pycurl时,我收到以下错误.不知道如何解决它.请帮忙 !!!
nsh$ sudo easy_install pycurl
Searching for pycurl
Reading http://pypi.python.org/simple/pycurl/
Reading http://pycurl.sourceforge.net/
Reading http://pycurl.sourceforge.net/download/
Best match: pycurl 7.19.0
Downloading http://pycurl.sourceforge.net/download/pycurl-7.19.0.tar.gz
Processing pycurl-7.19.0.tar.gz
Running pycurl-7.19.0/setup.py -q bdist_egg --dist-dir /tmp/easy_install-tU3r7x/pycurl-7.19.0 /egg-dist-tmp-XBXPV8
Using curl-config (libcurl 7.19.7)
unable to execute gcc-4.2: No such file or directory
error: Setup script exited with error: command 'gcc-4.2' failed with exit status 1
nsh$