我正在从我的矢量创建一个excel表,其中包含127923条记录,当我尝试输入记录时,我会遇到异常.
jxl.write.biff.RowsExceededException: The maximum number of rows permitted on a worksheet been exceeded
at jxl.write.biff.WritableSheetImpl.getRowRecord(WritableSheetImpl.java:1214)
at jxl.write.biff.WritableSheetImpl.addCell(WritableSheetImpl.java:1151)
at com.ibm.database.excel.WriteExcel.addLabel(WriteExcel.java:176)
at com.ibm.database.excel.WriteExcel.write(WriteExcel.java:76)
at com.ibm.database.excel.FileGenerator.generateExcel(FileGenerator.java:13)
at com.ibm.database.taxoreader.TaxonomyReader.main(TaxonomyReader.java:46)
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我知道因为excel表不允许超过65536条记录,但是我的代码我试图创建一个新的表单,每次我达到60000标记,但它不起作用.任何人都可以告诉我,我做错了什么.这是我的代码.
public void write (Vector list) throws IOException, WriteException{
int k=0,row=0,column=0;
WritableFont times10pt = new WritableFont(WritableFont.TIMES, 10);
// Define the cell format
times = new WritableCellFormat(times10pt);
// Lets automatically wrap the cells
times.setWrap(true);
TaxonomyBean bean= null;
File file = new File("Test.xls");
WorkbookSettings wbSettings = new WorkbookSettings();
wbSettings.setLocale(new Locale("en", "EN"));
WritableWorkbook workbook = Workbook.createWorkbook(file, wbSettings);
WritableSheet …Run Code Online (Sandbox Code Playgroud) 可能重复:
PHP中的语言构造和"内置"函数有什么区别?
我已经读过在php编程书中"Language construct such asecho()andisset()can not be called through variable function"
是什么意思呢?
我有一个使用以下代码创建的JButton.
JButton button = new JButton ( "Document",appletRec.getIcon()) ;
button.addActionListener ( this ) ;
button.setOpaque ( true ) ; //changed false from true.
button.setFocusPainted ( true ) ; //changed false from true.
button.actAsLink ( true ) ;
button.setHighlightForeground ( Color.blue ) ;
button.setVerticalTextPosition ( SwingConstants.BOTTOM ) ;
button.setVerticalAlignment ( SwingConstants.TOP ) ;
button.setHorizontalTextPosition ( SwingConstants.CENTER ) ;
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但我的按钮看起来像这样

我想将文本移动到按钮的底部.任何建议都高度赞赏.
我正在使用Code Pro来查看我的应用程序代码,并使用以下消息报告该工具:
警告:使用布尔文字进行相等性测试
对于此代码:
boolean valid;
if(valid == true)
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可以使用以下方法修复:
if(valid)
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我有两个问题:
我不确定这是否可行,但我有一个旧的java应用程序项目,其中包含1000多个java文件.我正在尝试将log4j支持添加到需要我添加的应用程序中
public static Logger logger = Logger.getLogger(MyClass.class.getName());
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在每个文件中.
我有什么方法可以使用eclipse执行操作.我试过source->format但是不允许我添加这一行.我是否必须打开每个文件并添加该行?
它在Java语言规范中提到
字符串文字总是String类型(§4.3.3).行终止符在打开"和结束匹配之前"之后出现是编译时错误.
如§3.4所述,字符CR和LF从不是InputCharacter; 每个被认为构成LineTerminator.
但我可以创建并运行以下语句
public class StringOperation {
public static void main(String ...args){
String first = "\n";
System.out.println(first);
}
}
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我没有看到任何错误.感谢所有的见解.
我正在使用 swagger 3.0.0-SNAPSHOT 和 spring-data-rest。我的应用程序属性文件中有上下文配置
server.servlet.context-path=/sample/
我的swagger配置如下:
@Configuration
@EnableSwagger2WebMvc
@Import({springfox.documentation.spring.data.rest.configuration.SpringDataRestConfiguration.class})
public class SwaggerConfig {
@Bean
public Docket api(){
return new Docket(DocumentationType.SWAGGER_2)
.select()
.apis(RequestHandlerSelectors.any())
.paths(PathSelectors.any())
.build();
}
}
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我正在访问我的 swagger ui http://localhost:8080/sample/swagger-ui.html
招摇中的所有终点看起来像
http://locahost:8080/sample/sample/getHello
http://locahost:8080/sample/sample/getName
http://locahost:8080/sample/sample/getAge
这些网址应该是
http://locahost:8080/sample/getHello
http://locahost:8080/sample/getName
http://locahost:8080/sample/getAge
如何避免大肆向端点添加额外的上下文根
我的 RestController 看起来像
@RestController
public class HelloController {
@RequestMapping("/hello")
public String getHello(){
return "Hello";
}
@RequestMapping("/name")
public String getName(){
return "Sample Name";
}
@RequestMapping("/age")
public Integer getAge(){
return 37;
}
}
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我已经通过一个示例项目确认了这种情况在每种情况下都会发生
我的 Maven 项目遇到奇怪的错误。当我编译项目时,我收到以下异常
[ERROR] (use -source 5 or higher to enable for-each loops)
[ERROR] /home/ashish/code/arena/JUnit/src/main/java/com/tutorial/junit/controller/DefaultController.java:[14,15] error: generics are not supported in -source 1.3
[ERROR] -> [Help 1]
org.apache.maven.lifecycle.LifecycleExecutionException: Failed to execute goal org.apache.maven.plugins:maven-compiler-plugin:2.0.2:compile (default-compile) on project junit: Compilation failure
at org.apache.maven.lifecycle.internal.MojoExecutor.execute(MojoExecutor.java:213)
at org.apache.maven.lifecycle.internal.MojoExecutor.execute(MojoExecutor.java:153)
at org.apache.maven.lifecycle.internal.MojoExecutor.execute(MojoExecutor.java:145)
at org.apache.maven.lifecycle.internal.LifecycleModuleBuilder.buildProject(LifecycleModuleBuilder.java:84)
at org.apache.maven.lifecycle.internal.LifecycleModuleBuilder.buildProject(LifecycleModuleBuilder.java:59)
at org.apache.maven.lifecycle.internal.LifecycleStarter.singleThreadedBuild(LifecycleStarter.java:183)
at org.apache.maven.lifecycle.internal.LifecycleStarter.execute(LifecycleStarter.java:161)
at org.apache.maven.DefaultMaven.doExecute(DefaultMaven.java:320)
at org.apache.maven.DefaultMaven.execute(DefaultMaven.java:156)
at org.apache.maven.cli.MavenCli.execute(MavenCli.java:537)
at org.apache.maven.cli.MavenCli.doMain(MavenCli.java:196)
at org.apache.maven.cli.MavenCli.main(MavenCli.java:141)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:483)
at org.codehaus.plexus.classworlds.launcher.Launcher.launchEnhanced(Launcher.java:289)
at org.codehaus.plexus.classworlds.launcher.Launcher.launch(Launcher.java:229)
at org.codehaus.plexus.classworlds.launcher.Launcher.mainWithExitCode(Launcher.java:415)
at org.codehaus.plexus.classworlds.launcher.Launcher.main(Launcher.java:356) …Run Code Online (Sandbox Code Playgroud) 我刚刚开始学习Angular JS,我正在尝试使用ng-repeat创建一个8X8表.我无法获得8个表头.所有表头都在一列中.这是我的代码.
<table border="1px solid black">
<tr ng-repeat="k in [0,1,2,3,4,5,6,7,8]">
<th>
column
</th>
</tr>
<tr ng-repeat="i in [0,1,2,3,4,5,6,7,8]">
<td ng-repeat="j in [0,1,2,3,4,5,6,7,8]">
[{{i}},{{j}}]
</td>
</tr>
</table>
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这是我的代码的输出.我不确定为什么会这样.

我正在使用 Flask 和来自http://flask.pocoo.org/docs/1.0/tutorial/factory/ 的教程构建一个 python web 应用程序。我正在从父目录运行烧瓶,但出现以下错误。
(venv) E:\python-code\python-web>flask run
* Serving Flask app "flaskr" (lazy loading)
* Environment: development
* Debug mode: on
* Restarting with stat
* Debugger is active!
* Debugger PIN: 294-690-396
* Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
127.0.0.1 - - [16/Mar/2019 13:10:43] "GET /hello HTTP/1.1" 500 -
Traceback (most recent call last):
File "e:\python-code\python-web\venv\lib\site-packages\flask\_compat.py", line 35, in reraise
raise value
File "e:\python-code\python-web\venv\lib\site-packages\flask\cli.py", line 95, in find_best_app
module=module.__name__
flask.cli.NoAppException: Failed to find …Run Code Online (Sandbox Code Playgroud)