小编Cor*_*lom的帖子

假设我有效果

@Effect()
someEffect$ = this.actions$.pipe(ofType(X), switchMap(() => 
of(Y).pipe(delay(3000)))

大理石测试应该是什么样子的？

const action = new X();
const result = new Y();

actions$.stream = hot('-x', { x: action });
const expected = cold('-y', { y: result }); // ? adding frames or 3s doesn't work
expect(effects.someEffect$).toBeObservable(expected);

作为回报，我得到

Expected $.lenght = 0 to equal 1.