小编goa*_*ker的帖子

代码: var foo = /\</;

当我去jslint.com并输入时,我得到:

Problem at line 1 character 12: Unexpected '\'.

它曾经告诉我,Unexpected escaped character '<' in regular expression.但时代已经改变.

所以我只是好奇,为什么？如果你尝试var foo = /\>/;它不关心,有什么处理<？