我正在尝试使用以下代码将 pandas 对象保存到镶木地板中:
LABL = datetime.now().strftime("%Y%m%d_%H%M%S")
df.to_parquet("/data/TargetData_Raw_{}.parquet".format(LABL))
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这给了我错误:
ArrowTypeError: ("Expected bytes, got a 'float' object", 'Conversion failed for column Pre-Rumour_Date with type object')
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pandas 的数据类型如下:
0
Announced_Date object
Completed_Date object
Pre-Rumour_Date object
object
Lapsed_Date object
Target_Company object
Bidder_Company object
Seller_Company object
Deal_Value_USD(_m) object
Exit_Type object
Buy_Type object
Sell_Stake_(%) object
Buy_Stake_(%) object
Months_Held object
Private_Equity_House object
ADATE datetime64[ns]
dtype: object
Run Code Online (Sandbox Code Playgroud) 这是来自 Leetcode 804: Unique Morse Code Words。我想知道为什么我的代码给出了正确的莫尔斯电码,但它是按字母顺序排序的,这不是故意的。任何贡献表示赞赏。
输入:
words = ["gin", "zen", "gig", "msg"]
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代码:
class Solution:
def uniqueMorseRepresentations(self, words: List[str]) -> int:
morse = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
alphabet = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
transformation = []
zip_ = list(zip(morse, alphabet))
for word in words:
transformation.append(''.join(code[0] for code in zip_ for letter in word if letter in code[1]))
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输出:
['--...-.', '.-.--..', '--.--...', '--.--...']
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