以下代码未进入i for循环.我的电脑和VS2010出了问题.这是编码问题(我是编程c#.net的vb.net程序员)还是vb安装问题？
for(int hi = 1; hi > 10; hi++)
{
reply = pingsender.Send(ip, 500, buffer, options);
avgtime += reply.RoundtripTime;
}
//EDIT:
//All code except for issue taken offline due to company policy
//sorry for any inconvience
这段代码嵌套在四个for循环中(一切都工作)并且是runnin,并且用于将ping统计信息放在列表框中.对不起凌乱的代码,我在代码工作后发表评论和清理.
提前感谢您的辛勤工作!
我正在开发一个应用程序，该应用程序允许用户使用他们的 google 帐户登录，然后使用该登录名获取 Cognito 联合身份。
我无法获得使用 Cognito 进行身份验证所需的正确令牌。我不断收到错误com.amazonaws.services.cognitoidentity.model.NotAuthorizedException: Invalid login token. Not a valid OpenId Connect identity token.
这是我的代码：
Runnable runnable = new Runnable() {
@Override
public void run() {
CognitoSyncClientManager.init(getActivity().getApplicationContext());
String token = null;
try {
token = GoogleAuthUtil.getToken(getActivity().getApplicationContext(), signInAccount.getAccount(), "oauth2:openid");
}catch (Exception e){
Log.d("login exception", e.toString());
}
Map<String, String> logins = new HashMap<String, String>();
logins.put("accounts.google.com", token);
CognitoSyncClientManager.addLogins("accounts.google.com", token);
Log.d("login", "Created User token " + token);
Log.d("login", "Cached UserID: "+CognitoSyncClientManager.credentialsProvider.getCachedIdentityId());
Log.d("login", "UserID: " + CognitoSyncClientManager.credentialsProvider.getIdentityId());
Toast.makeText(getActivity().getApplicationContext(), "Created user: …openid google-openid openid-connect amazon-cognito aws-cognito
我在一个简单的表单上绘制图形时遇到问题.我的代码编译并运行,但目标红框不会显示.
我在Visual Studio 2010中使用完整的.NET Framework 4.
出了什么问题,如何解决？
private void Form1_Load(object sender, EventArgs e)
{
System.Drawing.Graphics graphicsObj;
graphicsObj = this.CreateGraphics();
Pen myPen = new Pen(System.Drawing.Color.Red, 5);
Rectangle myRectangle = new Rectangle(20, 20, 250, 200);
graphicsObj.DrawRectangle(myPen, myRectangle);
}
编辑:工作但代码慢
void BatteryPaint(object sender, EventArgs e)
{
TabPage page = (TabPage)sender;
if (!controlsSetup)
{
populateBatteryTab(page);
controlsSetup = true;
}
//Create the items
Rectangle busBar = new Rectangle();
Rectangle batPack = new Rectangle();
Rectangle pack1Outline = new Rectangle();
Rectangle pack2Outline = new Rectangle();
Rectangle pack3Outline …我正在尝试使用以下代码，但无法使其正常工作。即使我完全按照文档中的说明进行操作，也会不断给我关于过滤器表达式类型错误的错误消息。我该怎么做才能解决此问题？
def EndpointDeleted(event):
endpoint = event['Attributes']['EndpointArn']
if('EndpointArn' in event['Attributes']):
client = boto3.client('dynamodb')
response = client.scan(
TableName='sniffergps-mobilehub-812282467-Users',
Select='ALL_ATTRIBUTES',
FilterExpression=Attr('Endpoints').contains(endpoint)
)
return response但是我收到一个错误消息，说过滤器表达式是错误的类型。我有以下导入消息：
import boto3
from boto3.dynamodb.conditions import Key
from boto3.dynamodb.conditions import Attr
错误信息：
{
"errorMessage": "Parameter validation failed:\nInvalid type for parameter FilterExpression, value: <boto3.dynamodb.conditions.Contains object at 0x7fdca25e0b38>, type: <class 'boto3.dynamodb.conditions.Contains'>, valid types: <class 'str'>",
"errorType": "ParamValidationError",
"stackTrace": [
[
"/var/task/lambda_function.py",
13,
"lambda_handler",
"return EndpointDeleted(event)"
],
[
"/var/task/lambda_function.py",
24,
"EndpointDeleted",
"FilterExpression=Attr('Endpoints').contains(endpoint)"
],
[
"/var/runtime/botocore/client.py",
312,
"_api_call",
"return …