我使用以下bash脚本仅复制某些扩展名的文件(在本例中为*.sh),但它仍然复制所有文件.怎么了?
from=$1 to=$2 rsync -zarv --include="*.sh" $from $to
如何使用linux mail命令在电子邮件中插入新行?
echo "Hi xxx, would you tell me something?\\n thanks!\\n -xxx" | mail -s "subject" xxx@gmail.com
Run Code Online (Sandbox Code Playgroud)
电子邮件显示文字'\n',而不是换行符,如何解决?
我在许多不同的物理服务器上有一个大的分布式程序,每个程序产生许多线程,每个线程Math.random()在其操作中使用从许多公共资源池中抽取一块.
目标是在所有操作中均匀地使用池.有时,通过查看资源池上的快照看它在那一瞬间得到哪些部分(实际上可能是这样,但很难测量并确定),它似乎并不是随机的.
是否有比这更好的东西Math.random()(至少不是更糟)?
ip是一对一映射的主机名吗?主机名如何有多个IP地址?根据Java的getAllByName,它返回一个hostName的ips列表,但是它的文档似乎暗示或者至少没有解释一对多的映射:
The host name can either be a machine name, such as "java.sun.com", or a textual representation of its IP address.
如何根据ip确定位置?我不是要求任何产品或服务,而是如何在技术上实施它.
ip to country是一个相当静态的映射.更具体的位置怎么样?
是否可以使用java.util.Logging并登录到java webstart应用程序中的文件?我有以下日志代码:
Handler fh = new FileHandler("myapp.log");
Logger.getLogger(MyApp.class.getName()).addHandler(fh);
并得到以下例外:
java.security.AccessControlException: access denied (java.util.logging.LoggingPermission control)
at java.security.AccessControlContext.checkPermission(Unknown Source)
at java.security.AccessController.checkPermission(Unknown Source)
at java.lang.SecurityManager.checkPermission(Unknown Source)
at java.util.logging.LogManager.checkAccess(Unknown Source)
at java.util.logging.Handler.checkAccess(Unknown Source)
at java.util.logging.FileHandler.(Unknown Source)
at whoisapiclient.WhoisAPIClientApp.main(WhoisAPIClientApp.java:80)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source)
at java.lang.reflect.Method.invoke(Unknown Source)
at com.sun.javaws.Launcher.executeApplication(Unknown Source)
at com.sun.javaws.Launcher.executeMainClass(Unknown Source)
at com.sun.javaws.Launcher.doLaunchApp(Unknown Source)
at com.sun.javaws.Launcher.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
我有以下hibernate xml映射文件段.
<list name="networks" cascade="all">
<key column="parent_id"/>
<one-to-many class="Network"/>
</list>
它产生了以下异常,为什么?它确实有上述元素.
Caused by: org.xml.sax.SAXParseException: The content of element type "list" must match "(meta*,subselect?,cache?,synchronize*,comment?,key,(index|list-index),(element|one-to-many|many-to-many|composite-element|many-to-any),loader?,sql-insert?,sql-update?,sql-delete?,sql-delete-all?,filter*)".
at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
at org.apache.xerces.util.ErrorHandlerWrapper.error(Unknown Source)
at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)
at org.apache.xerces.impl.dtd.XMLDTDValidator.handleEndElement(Unknown Source)
at org.apache.xerces.impl.dtd.XMLDTDValidator.endElement(Unknown Source)
at org.apache.xerces.impl.XMLNSDocumentScannerImpl.scanEndElement(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
at org.dom4j.io.SAXReader.read(SAXReader.java:465)
at org.hibernate.cfg.Configuratio
我在一个目录中递归地将文件放在一起,但是,有些文件在最后一行之后缺少换行符,因此这会产生问题。
如何在进程中为每个文件附加换行符?这是shellscript
find $1 -type f |xargs cat > test.csv
我有一个文件,它是comm命令的结果,它有2列,我希望将这两列分成两个不同的文件,我该怎么做?
该文件看起来像:
a
b
g
f
c
d
我有一个庞大的mysql数据库和centos上的两个小磁盘,如何让它利用两个磁盘?