我有一个通过AbstractTableModel填充链表的Jtable.
我想要做的是当我点击(左键单击)JTable中的一行时,链表是搜索(在这种情况下它包含电影标题)并在Jtextboxes中的链表中显示值
我该怎么做呢?
这是代码
我猜它会将所选行中的数据检索到一个数组中,将其拆分并放入jtextareas中.我怎样才能做到这一点 ?
可能重复:
PHP获取给定目录的所有子目录
我想要一个下拉菜单,以显示所有子目录,./files/$userid/
而不仅仅是主文件夹.例如: /files/$userid/folder1/folder2/
我目前的代码是:
HTML:
<select name="myDirs">
<option value="" selected="selected">Select a folder</option>
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PHP:
if (chdir("./files/" . $userid)) {
$dirs = glob('*', GLOB_ONLYDIR);
foreach($dirs as $val){
echo '<option value="'.$val.'">'.$val."</option>\n";
}
} else {
echo 'Changing directory failed.';
}
Run Code Online (Sandbox Code Playgroud) 我正在尝试从Android Studio运行应用程序,但AVD无法启动.虽然模拟器加载部分完成(模拟器未打开但进度条完成),但它依赖于"等待目标设备上线".
终端输出:
brian@brian-desktop:~/Downloads/android-studio/bin$ ./studio.sh
Looking in classpath from com.intellij.util.lang.UrlClassLoader@6d5380c2 for /com/sun/jna/linux-x86-64/libjnidispatch.so
Found library resource at jar:file:/home/brian/Downloads/android-studio/lib/jna.jar!/com/sun/jna/linux-x86-64/libjnidispatch.so
Trying /home/brian/.AndroidStudio2.3/system/tmp/jna3898264938984980367.tmp
Found jnidispatch at /home/brian/.AndroidStudio2.3/system/tmp/jna3898264938984980367.tmp
[ 6896] WARN - dea.updater.SdkComponentSource - File /home/brian/.android/repositories.cfg could not be loaded.
Downloading https://services.gradle.org/distributions/gradle-3.3-all.zip
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Unzipping /home/brian/.gradle/wrapper/dists/gradle-3.3-all/55gk2rcmfc6p2dg9u9ohc3hw9/gradle-3.3-all.zip to /home/brian/.gradle/wrapper/dists/gradle-3.3-all/55gk2rcmfc6p2dg9u9ohc3hw9
Set executable permissions for: /home/brian/.gradle/wrapper/dists/gradle-3.3-all/55gk2rcmfc6p2dg9u9ohc3hw9/gradle-3.3/bin/gradle
[ 349239] WARN - .workspace.NdkWorkspaceManager - NDK support for project 'Kryptomate' is disabled because it's not a valid Android project
Looking for library 'libnotify.so.4'
Adding paths from jna.library.path: null
Trying libnotify.so.4
Found library …
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我在尝试解析JSON时遇到错误:
SyntaxError: Unexpected token u in JSON at position 0(…) eFormsAtoZIndex.aspx:6558
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完整代码:http://pastebin.com/LXpJN8GF
相关守则:
$(document).ready(function() {
var rebuild = getParameterByName("rebuild");
var createdStructures = $('#AtoZContentDiv').children().length;
if ((rebuild !== undefined && rebuild !== null && rebuild.indexOf("true") === 0) || (createdStructures === 0)) {
// clean up pre-existing data
cleanUp();
// create container structure
createFormLinkContainers();
// Call SP web services to retrieve the information and create the A to Z
retrieveListData();
completeInitialization();
} else {
try {
aggregateAll = jQuery.parseJSON($('#hdnAggregateAll').val());
console.log(jQuery.parseJSON($('#hdnAggregateAll').val())); …
Run Code Online (Sandbox Code Playgroud) 每当我尝试登录SQL*Plus(11g标准版Win 64)时,我都会收到与某些连接错误相关的错误.
我尝试以sysdba身份登录并提供密码.
所有服务都已启动.我在Windows 7上.
任何帮助,将不胜感激.
我创建了一个脚本,该脚本基本上遍历站点及其子站点中的所有列表,并列出每个文档或项目的权限。
\n\n但是,该脚本可以正常工作,当写入 CSV 文件时,权限(成员 + 角色)字符串将被写入而System.Object[]
不是 CSV 输出中的正确字符串(例如Member: user123 Role: Full Control
)。
示例输出:
\n\n"Common Hover Panel Actions", "https://#######.####.###.##", "https://######.######.#####.####", "System.Object[]", " Ministry for Finance", "Master Page Gallery", "12/22/2015 8:34:39 AM", "_catalogs/masterpage/Display Templates/Search/Item_CommonHoverPanel_Actions.js", "12/22/2015 8:34:39 AM", "6.2763671875"\n
Run Code Online (Sandbox Code Playgroud)\n\n下面是脚本:
\n\nAdd-PSSnapin Microsoft.SharePoint.PowerShell\n\nfunction Get-DocInventory([string]$siteUrl) {\n $site = New-Object Microsoft.SharePoint.SPSite $siteUrl\n\n $i = 0;\n foreach ($web in $site.AllWebs) {\n\n $count = $site.AllWebs.Count\n foreach ($list in $web.Lists) {\n\n if ($list.BaseType -ne \xe2\x80\x9cDocumentLibrary\xe2\x80\x9d)\n {\n continue\n }\n\n foreach ($item …
Run Code Online (Sandbox Code Playgroud) 我有一个包含这段代码的php页面:
echo '<div id="popup" style="display:none">';
echo '<form id="AddForm" name="AddForm" method="get">';
echo '<table><tr>';
echo '<td>Software Name: </td><td><input type="text" id="SoftwareName"/></td></tr>';
echo '<tr><td>Software Type:</td><td><input type="text" id="SoftwareType"/></td></tr>';
echo '<tr><td>License Method:</td><td><input type="text" id="LicenseMethod"/></td></tr>';
echo '<tr><td><input type="button" value="Add" OnClick="opener.GetAddData();"></td><td></td>';
echo '</tr></table>';
echo '</form>';
echo '</div>';
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Buttan调用CreatePopup():
echo "<input type='submit' value='Add' OnClick='CreatePopup();'/>";
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我使用以下代码打开此div作为弹出窗口:
function CreatePopup()
{
var w = null;
w = window.open('index.php?List=SoftwareLicenseAllocations', 'test', 'height=125,width=300');
w.document.write( $("#popup").html());
w.document.close();
}
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从弹出窗口中获取文本框值的代码:
function GetAddData()
{
var SoftwareName = document.getElementById('SoftwareName').value;//.getElementById('SoftwareName').value;
var SoftwareType = document.getElementById('SoftwareType').value;
var LicenseMethod =document.getElementById('LicenseMethod').value;
alert(SoftwareName, …
Run Code Online (Sandbox Code Playgroud) 我正在尝试使用Java通过手工编码来创建GUI(不使用GUI工具).
我正在尝试创建类似下图的内容,但它并没有像我想要的那样出现.(它是由名为Pencil的模型应用程序创建的)
这是到目前为止的代码:
import java.awt.*;
import javax.swing.*;
import javax.swing.JTable;
public class GUI extends JFrame {
public void buildGui() {
JFrame frame = new JFrame("Hotel TV Scheduler");
Container contentPane = frame.getContentPane();
contentPane.setLayout(new FlowLayout());
JPanel mainPanel = new JPanel();
mainPanel.setLayout(new BorderLayout());
JPanel listPanel = new JPanel();
listPanel.setLayout(new FlowLayout());
JTable chOneTable = new JTable();
JTable chTwoTable = new JTable();
JTable listTable = new JTable();
JButton rmvChOneButton = new JButton("Remove Channel");
JButton rmvChTwoButton = new JButton("Remove Channel");
listPanel.add(chOneTable);
listPanel.add(chTwoTable);
listPanel.add(listTable);
listPanel.add(rmvChOneButton);
listPanel.add(rmvChTwoButton);
JPanel infoPanel …
Run Code Online (Sandbox Code Playgroud) 我正在尝试运行Project.aspx.当单击"查看配置文件"按钮时,Admin.apsx应该创建会话"project_id",以便两个SQLDataSource从Session("project_id")获取project_id值.
我收到这个错误:
Project.aspx
<%@ Page Title="" Language="VB" MasterPageFile="~/MasterPage.master" AutoEventWireup="false" CodeFile="Project.aspx.vb" Inherits="Project" %>
<%@ Register assembly="System.Web.DataVisualization, Version=4.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35" namespace="System.Web.UI.DataVisualization.Charting" tagprefix="asp" %>
<asp:Content ID="Content3" ContentPlaceHolderID="ContentPlaceHolder1" Runat="Server">
<div id="project-image"><asp:Image ID="Image1" runat="server" Height="124px" Width="93px" />
<asp:FormView ID="frmViewProject" runat="server" DataKeyNames="project_id" DataSourceID="SqlDataSource1" HorizontalAlign="Justify">
<EditItemTemplate>
project_id:
<asp:Label ID="project_idLabel1" runat="server" Text='<%# Eval("project_id") %>' />
<br />
project_type:
<asp:TextBox ID="project_typeTextBox" runat="server" Text='<%# Bind("project_type") %>' />
<br />
project_start:
<asp:TextBox ID="project_startTextBox" runat="server" Text='<%# Bind("project_start") %>' />
<br />
project_finish:
<asp:TextBox ID="project_finishTextBox" runat="server" Text='<%# Bind("project_finish") %>' />
<br …
Run Code Online (Sandbox Code Playgroud) 我有一个 config.ini 文件,其中包含 Web 应用程序的一些默认配置(使用 VS 2017 的 Flask)
我也想自己写一些配置。
我正在使用下面的代码尝试在该[keys]
部分中写入,变量是gkey
:
def writeKey(key):
Config = configparser.ConfigParser()
configFile = Path("config.ini")
if configFile.is_file() == False:
cfgfile = open("config.ini",'w')
else:
cfgfile = open("config.ini")
# add the settings to the structure of the file, and lets write it out...
Config.add_section('keys')
Config.set('gkey','key',True)
Config.write(cfgfile)
cfgfile.close()
gkey = encrypt(key)
writeKey(gkey)
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我收到以下错误:
Traceback (most recent call last):
File "C:\Users\blivo\documents\visual studio 2017\Projects\blivori2\blivori2\blivori2\functions\common.py", line 59, in <module>
writeKey(gkey)
File "C:\Users\blivo\documents\visual studio 2017\Projects\blivori2\blivori2\blivori2\functions\common.py", line 30, in writeKey …
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awt ×1
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json ×1
jtable ×1
jtextfield ×1
layout ×1
linked-list ×1
oracle ×1
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