psql有一个-q/ --quiet选项(环境变量QUIET). pg_restore没有安静的选择.是否有任何方法可以pg_restore不冗长地显示它正在执行的SQL命令?
# e.g., here's the verbose output that I don't want to see:
$ pg_restore --cluster 8.4/mycluster mycluster.dump
---- PostgreSQL database dump
--
SET statement_timeout = 0;SET client_encoding = 'UTF8';
SET standard_conforming_strings = off;SET check_function_bodies = false;
...
--
-- Name: data_src; Type: TABLE; Schema: public; Owner: postgres; Tablespace:--
CREATE TABLE data_src (
...
Run Code Online (Sandbox Code Playgroud) 我有一个分支,我有一个提交只修改空格(尾随空格和前导空格).
我跑了git rebase master,git rebase --ignore-whitespace master并且在两种情况下我都与只改变空格的提交有合并冲突.
如何列出.txt不以换行符结尾的普通text()文件名?
例如:list(输出)这个文件名:
$ cat a.txt
asdfasdlsad4randomcharsf
asdfasdfaasdf43randomcharssdf
$
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并且不列出(输出)此文件名:
$ cat b.txt
asdfasdlsad4randomcharsf
asdfasdfaasdf43randomcharssdf
$
Run Code Online (Sandbox Code Playgroud) 当名称相同时,python如何区分类属性,实例属性和方法?
class Exam(object):
test = "class var"
def __init__(self, n):
self.test = n
def test(self):
print "method : ",self.test
test_o = Exam("Fine")
print dir(test_o)
print Exam.test
print test_o.test
test_o.test()
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输出:
['__class__', '__delattr__', '__dict__', '__doc__', '__format__', '__getattribute__', '__hash__', '__init__', '__module__', '__new__', '__reduce__', '__reduce_ex__', '__repr__', '__setattr__', '__sizeof__', '__str__', '__subclasshook__', '__weakref__', 'test']
<unbound method load.test>
Fine
Traceback (most recent call last):
File "example.py", line 32, in <module>
test_o.test()
TypeError: 'str' object is not callable
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怎么打电话
Exam.test- > <unbound method load.test>output显示方法 …在vundle的主页上,它记录了它需要在.vimrc中关闭文件类型:
filetype off " required!
set rtp+=~/.vim/bundle/vundle/
call vundle#rc()
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我不明白为什么.由于我在为它们单独安装相关插件(vim-coffee-script和vim-less)后最近编辑.coffee和.less文件时遇到问题.关于vim-coffee-script的问题
在Django文档中,最新的Meta选项列表在哪里django.forms.models.ModelForm?(例如model,exclude,fields,widgets)我正在寻找的等效模型Meta选项.
如何修改以下代码,以便在zsh中运行时,它会一次扩展$things并遍历它们?
things="one two"
for one_thing in $things; do
echo $one_thing
done
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我希望输出为:
one
two
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但如上所述,它输出:
one two
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(我正在寻找在bash中运行上述代码时获得的行为)
我必须编写一个命令行界面,我已经看到我可以使用docopt和argparse.
我想知道两者之间的主要区别是什么,这样我才能做出明智的选择.
请坚持事实.我不想哇.docopt.如此美丽.很有用.
我想获得每个客户的最新购买清单,按日期排序.
以下查询执行我想要的日期除外:
(Purchase.objects
.all()
.distinct('customer')
.order_by('customer', '-date'))
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它会产生如下查询:
SELECT DISTINCT ON
"shop_purchase.customer_id"
"shop_purchase.id"
"shop_purchase.date"
FROM "shop_purchase"
ORDER BY "shop_purchase.customer_id" ASC,
"shop_purchase.date" DESC;
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我被迫使用customer_id作为第一个ORDER BY表达因为DISTINCT ON.
我想按日期排序,所以我真正需要的查询应该是这样的:
SELECT * FROM (
SELECT DISTINCT ON
"shop_purchase.customer_id"
"shop_purchase.id"
"shop_purchase.date"
FROM "shop_purchase"
ORDER BY "shop_purchase.customer_id" ASC,
"shop_purchase.date" DESC;
)
AS result
ORDER BY date DESC;
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我不想使用python排序,因为我仍然需要页面限制查询.数据库中可能有数万行.
实际上它现在在python中排序,并且导致非常长的页面加载时间,所以这就是我试图解决这个问题的原因.
基本上我想要这样的东西/sf/answers/685727311/.是否可以用django查询集来表达它而不是编写原始SQL?
实际的模型和方法有几页长,但这里是上面的查询集所需的模型集.
class Customer(models.Model):
user = models.OneToOneField(User)
class Purchase(models.Model):
customer = models.ForeignKey(Customer)
date = models.DateField(auto_now_add=True)
item = models.CharField(max_length=255)
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如果我有以下数据: …
我想搜索可选的出现位置ad和abcd位置bc.我怎样才能做到这一点?即
+-------+----------+
| ad | MATCH |
| abcd | MATCH |
| abd | NO match |
| abbd | NO match |
| abced | NO match |
| abcbcd| NO match |
+-------+----------+
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