小编laz*_*laz的帖子

我无法弄清楚如何配置我的log4j,以便我的debugLog和我的reportLog彼此分开(不是附加的).为什么,在下面的配置中,reportsLog始终为空？

log4j.rootLogger=TRACE, stdout, debugLog

log4j.appender.stdout=org.apache.log4j.ConsoleAppender
log4j.appender.stdout.layout=org.apache.log4j.PatternLayout
log4j.appender.stdout.layout.ConversionPattern=%d [%24F:%t:%L] - %m%n

log4j.appender.debugLog=org.apache.log4j.FileAppender
log4j.appender.debugLog.File=logs/debug.log
log4j.appender.debugLog.layout=org.apache.log4j.PatternLayout
log4j.appender.debugLog.layout.ConversionPattern=%d [%24F:%t:%L] - %m%n

log4j.reportsLog=DEBUG,reportsLog
log4j.appender.reportsLog=org.apache.log4j.FileAppender
log4j.appender.reportsLog.File=logs/reports.log
log4j.appender.reportsLog.layout=org.apache.log4j.PatternLayout
log4j.appender.reportsLog.layout.ConversionPattern=%d [%24F:%t:%L] - %m%n

这是我的Java代码:

package test;

import org.apache.log4j.Logger;
import org.apache.log4j.PropertyConfigurator;

public class HelloLogger {

    static final Logger debugLog = Logger.getLogger("debugLog");
    static final Logger resultLog = Logger.getLogger("reportsLog");

    public static void main(String[] args) {
        PropertyConfigurator.configure("log4j.properties");
        debugLog.debug("Hello debugLog message");   
        resultLog.debug("Hello reportsLog message");
    }   
}

我正在尝试在java中为我正在处理的Android应用发布一些JSON数据.以下是有效的还是我需要以不同的方式推送JSON字符串？

HttpPost httpost = new HttpPost("http://test.localhost");
httpost.setEntity(new StringEntity("{\"filters\":true}"));
httpost.setHeader("Accept", "application/json");
httpost.setHeader("Content-type", "application/x-www-form-urlencoded; charset=UTF-8");
//... other java code to execute the apache httpclient

先感谢您

有没有一种简单的方法来拦截java中的方法.我需要为所需的方法添加一个注释,以便在通过该方法之前调用一段逻辑.

public void verifyActivity() {
   // Asset if you are on a wrong page
}

@VerifyActivity
public void testLogin() {
   // Login for my automate test
}

@VerifyActivity
public void testSomethingElse() {
   // Test some other UI Automation stuff
}

编辑:

Android应用程序推荐的guice库不包含AOP.是否可以在不添加任何库的情况下使用反射实现此目的？

我正在使用一种非常标准的Java AES加密/解密方式.

byte[] key = hexStringToByteArray("C0C1C2C3C4C5C6C7C8C9CACBCCCDCECF");

byte[] message = hexStringToByteArray("01A0A1A2A3A4A5A6A703020100060001");

SecretKeySpec secretKeySpec = new SecretKeySpec(key, "AES");

// Instantiate the cipher
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.ENCRYPT_MODE, secretKeySpec);

byte[] encrypted = cipher.doFinal(message);

cipher.init(Cipher.DECRYPT_MODE, secretKeySpec);
byte[] original = cipher.doFinal(encrypted);

如您所见,我使用的是128位密钥和128位消息.我总是得到我期望的结果,但加密结果总是256位长.第二个128位始终相同.截断结果除外,如何确保密码只返回前128位,而不更改前128位？我觉得我有点混淆块大小的定义.

import java.util.*;

public class Test {
    public static void main(String[] args) {

        List db = new ArrayList();

        ShopDatabase sb = new ShopDatabase(db);
        sb.addEntry(new ProductEntry("film", 30, 400));
        sb.addEntry(new CashierEntry("Kate", "Smith", 23, 600));
        sb.addEntry(new ManagerEntry("Jack", "Simpson", 1, 700));
        sb.addEntry(new ProductEntry("soap", 18, 3));
        sb.addEntry(new ManagerEntry("Helen", "Jones", 60, 650));
        sb.addEntry(new CashierEntry("Jane", "Tomson", 15, 900));
        sb.addEntry(new ProductEntry("shampoo", 25, 5));
        sb.addEntry(new CashierEntry("Bill", "Black", 59, 300));
        Collections.sort(db);
        Iterator itr = db.iterator();

        while (itr.hasNext()) {
            Entry element = (Entry) itr.next();
            System.out.println(element + "\n");
        }
    }
}

public abstract …