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Firebase 可调用函数未接收参数

在打字稿上实现一个简单的函数来调用 Firebase 可调用函数是行不通的。使用 firebase-tools@4.0.3 -g、firebase-functions@2.0.5、firebase@5.3.1

Firebase 可调用函数:

import * as functions from "firebase-functions";

exports.httpsOnCall = functions.https.onCall((data, context) => {
  console.log(data);
  return data;
});
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它部署正确

在 webapp 中调用函数:

const a = Firebase.functions.httpsCallable("httpsOnCall");
  a.call({ a: 1, b: "testing", c: true }).then(result => {
    console.log(result);
  });
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Firebase 对象初始化:

import * as firebase from "firebase";

const config = {
  apiKey: "asdasdasd",
  authDomain: "APPNAME.firebaseapp.com",
  databaseURL: "https://APPNAME.firebaseio.com",
  projectId: "APPNAME",
  storageBucket: "APPNAME.appspot.com",
  messagingSenderId: "123456"
};
firebase.initializeApp(config);
const Firebase = {
   functions: firebase.functions()
}
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从 Firebase 登录:

null …
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javascript firebase typescript google-cloud-functions

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