小编COL*_*OLD的帖子

如何将此SQL正确转换为linq

select  t1.ProgramID
from Program t1 LEFT JOIN ProgramLocation t2 ON  t1.ProgramID = t2.ProgramID 
where t2.ProgramID IS NULL

我尝试过,但它不起作用

var progy = (
             from u in db.ProgramLocations join b in db.Programs
             on u.ProgramID equals b.ProgramID into yG 
             from y1 in yG.DefaultIfEmpty() 
             where u.ProgramID == null
             where u.ProgramID == null 
             select u.ProgramID
            ).ToList();

谢谢

嗨我正在使用剃须刀并尝试使用正则表达式来验证电子邮件地址这里的验证功能

function validateEmail(txtEmail){
   var a = document.getElementById(txtEmail).value;
   var filter = /^[a-zA-Z0-9_.-]+@[a-zA-Z0-9]+[a-zA-Z0-9.-]+[a-zA-Z0-9]+.[a-z]{0,4}$/;
    if(filter.test(a)){
        return true;
    }
    else{
        return false;
    }
}?

但由于正则表达式有一个@符号razor认为它是语法的一部分,并给我一个错误.

无论如何要避免确保剃刀无视@登录JavaScript

谢谢.

这是我的客户端ajax调用:

    var list = ["a", "b", "c", "d"];

    var jsonText = { data: list };

    $.ajax({
        type: "POST",
        url: "/api/scheduledItemPriceStatus/updateStatusToDelete",
        data: jsonText,
        dataType: "json",
        traditional: true,
        success: function() { alert("it worked!"); },
        failure: function() { alert("not working..."); }
    });

这是chrome网络标题:

Request URL:http://localhost:2538/api/scheduledItemPriceStatus/updateStatusToDelete

Request Method:POST

Request Headersview source

Accept:application/json, text/javascript, */*; q=0.01

Accept-Charset:ISO-8859-1,utf-8;q=0.7,*;q=0.3

Accept-Encoding:gzip,deflate,sdch

Accept-Language:en-US,en;q=0.8

Connection:keep-alive

Content-Length:27

Content-Type:application/x-www-form-urlencoded; charset=UTF-8

Host:localhost:2538

Origin:http://localhost:2538

Referer:http://localhost:2538/Pricing/ScheduledItemPrices

User-Agent:Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/537.11 (KHTML, like Gecko) Chrome/23.0.1271.97 Safari/537.11

X-Requested-With:XMLHttpRequest

表格Dataview URL编码

data:a
data:b
data:c
data:d

这是我的webapi控制器方法: …