小编ppe*_*ree的帖子

我很确定我在这里犯了很多错误,但我不确定是什么......

表格(减去几个字段):

CREATE TABLE IF NOT EXISTS `stuff` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `lat` decimal(12,7) NOT NULL,
  `lon` decimal(12,7) NOT NULL,
  `location` point NOT NULL,  
  UNIQUE KEY `id` (`id`),
  KEY `distance` (`distance`),
  KEY `lat` (`lat`),
  KEY `lon` (`lon`),
  SPATIAL KEY `location` (`location`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci AUTO_INCREMENT=5;

自动设置位置点的触发器:

DROP TRIGGER IF EXISTS `stuff_insert_defaults`;
DELIMITER //
CREATE TRIGGER `stuff_insert_defaults` BEFORE INSERT ON `stuff`
 FOR EACH ROW SET NEW.location = PointFromText(CONCAT('POINT(',NEW.lat,' ',NEW.lon,')'))
//
DELIMITER ;

DROP TRIGGER IF EXISTS …

我有一排三个图像,目前显示正常.

现在,我想在这三个下面再显示两个图像,我希望它们居中(它看起来像一个倒置的金字塔).

无论我做什么,底行保持左对齐.

这是.css

.category
{
 width:176px; 
 font-size:80%; 
 text-align:center;
 float:left;
 position:relative;
}

这是html:

 <div style='width:95%; align:center'>
 <div class='category'><a href='individual.php'><img src='images/individual.jpg' style="padding-bottom:0.0em;" border='0' alt='Individual Electronic Neighborhood Watch Alerts by Email and Text Messaging'></a>
 <b>Individuals</b></div>        
 <div class='category'><a href='community.php'><img src='images/community.jpg' style="padding-bottom:0.0em;" border='0' alt='Community based Electronic Neighborhood Watch Alerts by Email and Text Messaging'></a>
 <b>Communities</b></div>        
 <div class='category'><a href='/police'><img src='images/first_respond.jpg' style="padding-bottom:0.0em;" border='0' alt='Police and send Electronic Neighborhood Watch Alerts by Email and Text Messaging'></a>
 <b>Fire/Police</b></div>
 <br>
 <div class='category'><a href='business.php'><img src='images/business.jpg' border='0' alt='Electronic Crime Watch Alerts …

我有两张桌子:

CREATE TABLE IF NOT EXISTS `test1` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `bucket_id` int(10) unsigned NOT NULL COMMENT 'folder this component belongs to',
  `test1_name` varchar(81) NOT NULL COMMENT 'Name of this component',
  `test1_desc` varchar(1024) NOT NULL COMMENT 'Component Description',
  PRIMARY KEY (`id`),
  FULLTEXT KEY `test1_search` (`test1_name`,`test1_desc`)
) ENGINE=MyISAM  DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 ;

CREATE TABLE IF NOT EXISTS `bucket` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `bkt_name` varchar(81) NOT NULL COMMENT 'The name of this bucket',
  `bkt_desc` varchar(1024) NOT …

我有一个iframe拉入图像和一些数据行(跨域).使用嵌入式javascript文件创建iframe,如下所示:

    <script type="text/javascript" src="http://www.domain.com/blah/scriptfile.js?blah_id=001" id="blah_script"></script>

正在创建iframe并且它完美地加载了图像和数据......到目前为止,非常好.

在iframe中我想隐藏数据行并缩短iframe的高度[ - ],当单击图像时[+]展开iframe的高度并取消隐藏行.我把行放在一个.

下面是被称为onclick的函数的缩减版本(并且它被调用).函数的第一行显示了我如何生成szFrameName,$ folder_id是001,它反映在szSpanName中.当alert()被调用时,它显示:"blah_iframe_001 blah_cmpnt_001"所以名称是正确的但是document.getElementById在blah_iframe上返回null但在blah_cmpnt_上工作正常

function onclickToggle()
{
  var szFrameName = 'blah_iframe_' +"<?php echo $folder_id; ?>";
  var szSpanName = "blah_cmpnt_" +"001";
  var idFrame = document.getElementById(szFrameName);
  var idCmpnt = document.getElementById(szSpanName);

  alert(szFrameName +" " +szSpanName);
}

我已经尝试过window.frameElement但是会产生"拒绝访问"错误,那么我该如何调整/缩短iframe呢？