我正在尝试使用时间轴绘制实时图形,但我发现LineChart构造函数只有签名.
LineChart(Axis<X> xAxis, Axis<Y> yAxis)
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我认为在javafx中嵌入jfree图表不是一个合适的解决方案.
我想在javafx中使用一些jfree功能LineChart,这可能吗?
我从一个活动调用javascript函数,但我收到Uncaught ReferenceError: myFunction is not defined at null:1错误.这是我的文件
MainActivity.java
package com.example.androidexample;
import android.os.Bundle;
import android.app.Activity;
import android.content.Context;
import android.view.Menu;
import android.webkit.WebChromeClient;
import android.webkit.WebSettings;
import android.webkit.WebView;
import android.webkit.WebViewClient;
import android.widget.Toast;
public class MainActivity extends Activity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
WebView webview = (WebView)this.findViewById(R.id.webView1);
WebSettings webSettings = webview.getSettings();
// Enable Javascript for interaction
webSettings.setJavaScriptEnabled(true);
// Make the zoom controls visible
webSettings.setBuiltInZoomControls(true);
// Allow for touching selecting/deselecting data series
webview.requestFocusFromTouch();
// Set the client
webview.setWebViewClient(new WebViewClient()); …Run Code Online (Sandbox Code Playgroud) 我想通过GSM调制解调器播放WAV文件.这是我的示例代码
private final int BUFFER_SIZE = 8;
private File soundFile;
private AudioInputStream audioStream;
private AudioFormat audioFormat;
public void playSound(String filename) throws IOException{
String strFilename = filename;
try {
soundFile = new File(strFilename);
} catch (Exception e) {
e.printStackTrace();
System.exit(1);
}
try {
audioStream = AudioSystem.getAudioInputStream(soundFile);
} catch (Exception e){
e.printStackTrace();
System.exit(1);
}
audioFormat = audioStream.getFormat();
DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
int nBytesRead = 0;
byte[] abData = new byte[BUFFER_SIZE];
while (nBytesRead != -1) {
try {
nBytesRead = audioStream.read(abData); …Run Code Online (Sandbox Code Playgroud) 由于javafx支持Raspberry PI.我想在帧缓冲区中运行FX应用程序.我正在使用Lubuntu LCD显示图像.
当我尝试运行JavaFX应用程序时
java -Djavafx.platform=eglfb Hello.jar
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我收到以下错误
我正在使用java8嵌入式hardfloat.
libEGL warning: DRI2: failed to authenticate
eglCreateWindowSurface failed! eglGetError 12291
eglMakeCurrent failed - 12288
Failed to create EGLContextGraphics Device initialization failed for : es2
Error initializing QuantumRenderer: no suitable pipeline found
java.lang.RuntimeException: java.lang.RuntimeException: Error initializing QuantumRenderer: no suitable pipeline found
at com.sun.javafx.tk.quantum.QuantumRenderer.getInstance(QuantumRenderer.java:300)
at com.sun.javafx.tk.quantum.QuantumToolkit.init(QuantumToolkit.java:244)
at com.sun.javafx.tk.Toolkit.getToolkit(Toolkit.java:179)
at com.sun.javafx.application.PlatformImpl.startup(PlatformImpl.java:214)
at com.sun.javafx.application.LauncherImpl.startToolkit(LauncherImpl.java:653)
at com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:314)
at com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:305)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:483)
at sun.launcher.LauncherHelper$FXHelper.main(LauncherHelper.java:767)
Caused by: java.lang.RuntimeException: Error initializing QuantumRenderer: …Run Code Online (Sandbox Code Playgroud) 我有这三种结构,
typedef struct serial_header {
int zigbeeMsgType;
int seqNumber;
int commandIdentifier;
int dest;
int src;
}serial_header_t;
typedef struct serial_packet {
serial_header_t header;
int data[];
} serial_packet_t;
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最后一个是
typedef struct readAttributePacket
{
int u8SourceEndPointId;
int u8DestinationEndPointId;
int u16ClusterId;
int bDirectionIsServerToClient;
int u8NumberOfAttributesInRequest;
int bIsManufacturerSpecific;
int u16ManufacturerCode;
int pu16AttributeRequestList[];
}readAttributePacket_t;
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我对此代码感到不安,我只想将驻留在serial_packet_t中的data []数组转换为readAttributePacket_t结构.我认为数据[]应该是
data[]={0x01,0x01,0x04,0x02,0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x01};
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我需要将这些数据转换为readAttributePacket_t结构.但是这下面的代码显示错误.
void main()
{
int a[]= {0x32,0x00,0x31,0x69,0x69,0x00,0x00,0x01,0x01,0x04,0x02,0x00,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x01};
int i;
readAttributePacket_t *p;
serial_packet_t *data;
data = (serial_packet_t*)&a;
for(i=0;i<20;i++){
printf(" %02x \n",a[i]);
}
p = (readAttributePacket_t *)&data->data;
printf("\nu8SourceEndPointId:%x \nu8DestinationEndPointId:%x \nu16ClusterId:%04x \nbDirectionIsServerToClient:%x …Run Code Online (Sandbox Code Playgroud) 我正在使用 JDeveloper 11g 开发桌面应用程序。我想制作可在java环境中运行的整个项目jar..如果我只使用标准Java库jar工作正常,但我的项目包含外部库,如JfreeChart、Comm、Hibernate3等...当我尝试制作jar时它显示错误如何使我的项目的整个 jar 以及外部库的。
谢谢
您好,我已经看到了为什么当端口存在时我会收到 Java NoSuchPortException?帖子,但对我来说不是很清楚!!
在设备管理器中,它显示 COM3 存在,我可以通过腻子连接它,但是这段代码出现了这个错误/异常。
try {
portId = CommPortIdentifier.getPortIdentifier("COM3");
} catch (NoSuchPortException ex) {
System.out.println(ex);
}
try {
serialPort = (SerialPort)portId.open("S2CFrameWork", 5000);
} catch (PortInUseException e) {
System.out.println(e);
}
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这个简单的代码抛出了一个 javax.comm.NoSuchPortException,我也尝试过使用枚举来获取可用端口列表,但它仍然显示异常。任何人都可以解决这个问题吗?
我正在使用java程序发送短信.
AT命令作为字符串提供.但字符串格式应该是这样的
AT+CMGS="+33146290800"<CR>Please call me soon.<ctrl-Z>.
我必须使用Carriage Return和CTRL-Z字符创建字符串.
输出:
AT+CMGS="+33146290800"13Please call me soon.26
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我怎样才能完成任务?任何人都可以帮我找到出路.
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