对我来说,这似乎是一项非常简单的任务,但即使经过大量研究和尝试,我也无法使其正常工作......
所以我有例如这个 URL,据我所知,这是一个 JSONObject 的 api?!
如果我在浏览器中打开此链接,则会得到以下结果:
{"images":[{"imageid":"1567153","imageurl_lg":"https://cf.geekdo-images.com/images/pic1567153_lg.jpg","name":null,"caption":"白色力量牌","numrecommend":"6","numcomments":"0","user":{"username":"manosdowns","avatar":"1","avatarfile":"avatar_id33829.jpg "},"imageurl":"https://cf.geekdo-images.com/6fCr14v025ZKYhXRMnbhYR16Ta8=/fit-in/200x150/pic1567153.jpg"}],"config":{"sorttypes":[{"type" :"hot","name":"Hot"},{"type":"recent","name":"Recent"}],"numitems":402,"endpage":402,"galleries":[ {“类型”:”all","name":"All"},{"type":"game","name":"Game"},{"type":"people","name":"People"},{" type":"creative","name":"Creative"}],"categories":[{"type":"","name":"All"},{"type":"BoxFront","name ":"BoxFront"},{"type":"BoxBack","name":"BoxBack"},{"type":"Components","name":"Components"},{"type":"自定义","name":"Customized"},{"type":"Play","name":"Play"},{"type":"Miscellaneous","name":"Miscellaneous"},{"type ":"Mature","name":"Mature"},{"type":"uncat","name":"Uncategorized"}],"licensefilters":[{"type":"","name":"Any "},{"type":"reuse","name":"允许复制"},{"type":"commercial","name":"允许商业使用"},{"type":"modify" ,"name":"允许修改"}],"datefilters":[{"value":"alltime","name":"All Time"},{"value":"today","name":"今天"},{"value":"twodays","name":"两天"},{"value":"last7","name":"Last 7 Days"},{"value":"last30","name":"Last 30 Days"},{"value":"year","name":"Last365 Days"}],"filters":[{"name":"Licenses"," listname":"licensefilters","type":"licensefilter"},{"name":"Category","listname":"categories","type":"tag"},{"name":"Gallery" ,"listname":"gallery","type":"gallery"}]}}Category","listname":"categories","type":"tag"},{"name":"Gallery","listname":"galleries","type":"gallery"}]}}Category","listname":"categories","type":"tag"},{"name":"Gallery","listname":"galleries","type":"gallery"}]}}
现在我的第一次尝试是像解析主页一样解析这个链接:
Run Code Online (Sandbox Code Playgroud)guard let myURL = URL(string: link) else { > print("Error: \(link) doesn't seem to be a valid URL") return } do { link = try String(contentsOf: myURL, encoding: .ascii) } catch let error { print("Error: \(error)") }
但这不起作用,因为我现在明白这是因为这是 JSON 编码?!
我搜索了解析 JSON 并找到了一些关于编码和解码的解释,但我的问题是,在给出的所有示例中,解释都是从“拥有”JsonObject 的内容开始的。我的问题是我可以在浏览器中读取 URL 的内容,但我需要 Xcode 本身中的 URL 内容,所以我可以解析它?!
所以在我的具体情况下,我只需要“imageurl_lg”的内容
...如果我可以在 Xcode 中显示我可以在浏览器中看到的内容,我会知道该怎么做 …