小编Len*_*rt-的帖子

我正在用C++制作一个程序,它使用2个图像来检测SURF特征,用bruteforcematcher计算匹配并绘制它.

这是代码

#include <cstdio>
#include <string>
#include <vector>
#include "opencv/cv.h"
#include "opencv/highgui.h"
#include "opencv2/features2d/features2d.hpp"


using namespace cv;
using namespace std;

int main(int argc, char **argv){
        if (argc <3) {
            cout << "Usage: " << argv[0] << " imageLocation1 imageLocation2" << endl;

            return -1;
        }

        Mat source1 = imread(argv[1],CV_LOAD_IMAGE_GRAYSCALE);
        Mat source2 = imread(argv[2],CV_LOAD_IMAGE_GRAYSCALE);
        if(source1.empty() || source2.empty()){
        printf("Can't load all the images!");
        return -1;
        }   

//Initialise the Wrapping Class for Surf()
    SurfFeatureDetector detector(400);

//detect : first param: Image, second param: vector (output) …

我们将我们的API从Django - Piston移植到Django-TastyPie.一切顺利,'直到我们达到这个目的:

应用程序的urls.py

 url(r'^upload/', Resource(UploadHandler, authentication=KeyAuthentication()), name="api-upload"),
    url(r'^result/(?P<uuid>[^//]+)/', Resource(ResultsHandler, authentication=KeyAuthentication()), name="api-result")

这使用活塞,所以我们想把它改成适合TastyPie的东西

url(r'^upload/', include(upload_handler.urls), name="api-upload"),
url(r'^result/(?P<uuid>[^//]+)/', include(results_handler.urls), name="api-result")

但我们坚持这个错误

使用参数'()'和关键字参数'{'uuid':'fbe7f421-b911-11e0-b721-001f5bf19720'}'找不到'api-result'.

和结果的调试页面:

使用MelodyService.urls中定义的URLconf,Django按以下顺序尝试了这些URL模式:

^ melotranscript/^ upload/^ melotranscript/^ result /(？P [^ //] +)/ ^(？Presultshandler)/ $ [name ='api_dispatch_list'] ^ melotranscript/^ result /(？P [^ // ] +)/ ^(？Presultshandler)/ schema/$ [name ='api_get_schema'] ^ melotranscript/^ result /(？P [^ //] +)/ ^(？Presultshandler)/ set /(？P\w [\ w /; - ]*)/ $ [name ='api_get_multiple'] ^ melotranscript/^ result /(？P [^ //] +)/ ^(？Presultshandler)/(？P\w [\ w/- ]*)/ $ [name ='api_dispatch_detail'] …

我正在寻找关于在Django中为OAuth编写两条腿提供程序的教程/示例/解释.

很难找到关于OAuth提供商的文档,甚至更难找到一个两足系统......