小编Asi*_*gir的帖子

可能重复:
Ajax请求问题:错误80020101

我使用的是JQuery-1.64,这是我重置计时器的代码

var message="Logged in";
var myTimeout = setTimeout("timerDone()",1000 * 1440);
function timerDone()
{
    message="Logged out";   
}
function timerReset()
{


    clearTimeout(myTimeout);
    myTimeout = setTimeout("timerDone()", 1000 * 1440);
}

但是当我尝试执行clearTimeout时,它只会在IE中出现错误.任何的想法？？？？

我正在尝试使用聚合与项目,匹配和排序,但我得到一个例外(MongoResultException确切地说)说

exception: A pipeline stage specification object must contain exactly one field.

当我没有使用排序和限制时它工作正常,但我需要它们.我不使用的原因是find()因为我在某处读到它可以提高性能.请帮忙

$query = array(.... //An actual query that works with find()
$collection = $this->db->CollectionName;
            $project = array(
                '$project'  => array(
                    'Field1'    => 1,
                    'Field2'=> 1,
                    'Field3'=> 1,
                    'Field4'      => 1
                )
            );
            $match = array( '$match'=>$query);
            $sort = array('Field3' => -1, 'Field4'=>-1);
            $limit = array('$limit' => 100);


            $result = $collection->aggregate(array($match,$project,$sort,$limit));
            return $result;

我想知道是否可以在viewwillappear方法中为uiscrollview设置contentoffset.

-(void) viewWillAppear:(BOOL)animated{

    [self.scrollView setContentOffset:CGPointMake(320, 0) animated:YES];
    NSLog(@"CALLED");    
}

我可以看到viewwillappear正在运行,但不幸的是它没有设置偏移量.

谢谢

我有侧面菜单,显示用户个人资料图片和用户名.当用户从我的设置页面更新这些信息时,它不会更新侧面菜单信息.

服务功能

//My service function
myApp.factory('User',function(Auth,dataService){

    var userInfo = null;

    return {
        getUserInfo:function(){
            if (userInfo == null){
                var loggedIn = Auth.isLoggedIn();
                var inputs = {auth_token:loggedIn.auth_token};
                console.log("Input User "+JSON.stringify(inputs));
                var promise = dataService.getUserInfo(inputs).then(function(response){
                    userInfo = response;
                    return response;
                });
                console.log("USERINFO IS "+ JSON.stringify(promise));
                return promise;
            }
            return userInfo;

        },
        refreshUserInfo:function(){
            var loggedIn = Auth.isLoggedIn();
            var inputs = {auth_token:loggedIn.auth_token};
            console.log("Input User "+JSON.stringify(inputs));
            var promise = dataService.getUserInfo(inputs).then(function(response){
                userInfo = response;
                return response;
            });

            return promise;
        }
    };
});

侧面菜单视图

 //Side menu View

     <ion-side-menu …

我正在尝试使用angularjs和cordova应用程序,我需要使用cordova插件,如地图和地理位置.我看过ngCordova,但是没有提供地图插件.出于测试目的,我试图添加地理位置插件但它根本不构建ios应用程序

clang: error: no such file or directory: '/Users/asifalamgir/Documents/hungryHaven/hungryHavenApp/platforms/ios/hungryHaven/Plugins/org.apache.cordova.geolocation/CDVLocation.m'
clang: error: no input files
Command /Applications/Xcode.app/Contents/Developer/Toolchains/XcodeDefault.xctoolchain/usr/bin/clang failed with exit code 1

** BUILD FAILED **


The following build commands failed:
    CompileC build/hungryHaven.build/Debug-iphonesimulator/hungryHaven.build/Objects-normal/i386/CDVLocation.o hungryHaven/Plugins/org.apache.cordova.geolocation/CDVLocation.m normal i386 objective-c com.apple.compilers.llvm.clang.1_0.compiler
(1 failure)
Error: /Users/asifalamgir/Documents/hungryHaven/hungryHavenApp/platforms/ios/cordova/build: Command failed with exit code 65
    at ChildProcess.whenDone (/usr/local/lib/node_modules/cordova/node_modules/cordova-lib/src/cordova/superspawn.js:135:23)
    at ChildProcess.emit (events.js:98:17)
    at maybeClose (child_process.js:756:16)
    at Process.ChildProcess._handle.onexit (child_process.js:823:5)

谢谢

在我的PHP代码中,我有

 <?php
      $test = json_encode($array);//$array is a valid multidimensional array
 ?>

我将此变量传递给javascript函数,我试图将此变量设置为javascript.

 <script>
     var test = "<?php echo $test;?>";
  </script>

(为了澄清我使用的是codeigniter框架,为简单起见,我没有使用我如何将变量发送到页面)

但是当我执行上面的代码时,我得到了

Uncaught SyntaxError: Unexpected identifier

我检查了所有语法.

先感谢您.