为什么(T)这个通用接口需要不安全的转换？如果T与自身相当,也就是ExtendedComparable<super of T>那些也意味着ExtendedComparable<T>,那么为什么需要ExtendedComparable<T>将类型擦除转换为T？
/* @param <T> T must be comparable to itself or any of its superclass
* (comparables are consumers, thus acc. to the PECS principle
* = producer-extends,consumer-super we use the bounded wildcard type "super")
*/
public interface ExtendedComparable<T extends ExtendedComparable<? super T>> {
Comparator<? super T> getComparator();
default boolean greaterThen(T toCompare) {
return getComparator().compare((T) this, toCompare) > 0;
}
}